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Schreiben Sie die folgende Doppelsumme aus: $$ \sum_{3 \leq i \leq 5,2 \leq j \leq 6} a_{i j} $$

Short Answer

Expert verified
The expanded sum is: \( a_{32} + a_{33} + a_{34} + a_{35} + a_{36} + a_{42} + a_{43} + a_{44} + a_{45} + a_{46} + a_{52} + a_{53} + a_{54} + a_{55} + a_{56} \).

Step by step solution

01

Understand the Sum Bounds

The given double summation is \( \sum_{3 \leq i \leq 5, 2 \leq j \leq 6} a_{ij} \). This indicates that we need to evaluate the sum over the indices \( i \) from 3 to 5 and \( j \) from 2 to 6. The variable \( a_{ij} \) denotes an element in a matrix or a sequence where the indices \( i \) and \( j \) are varying within the given ranges.
02

Expand the Outer Sum

Start by expanding the outer summation, which iterates over \( i \). We will write separate sums for each value of \( i \), where \( i = 3, 4, 5 \). For each \( i \), we will then expand the inner sum over \( j \).
03

Expand the Inner Sum for Each i Value

For \( i = 3 \), calculate the inner sum: \( \sum_{j=2}^{6} a_{3j} = a_{32} + a_{33} + a_{34} + a_{35} + a_{36} \).Next for \( i = 4 \), calculate: \( \sum_{j=2}^{6} a_{4j} = a_{42} + a_{43} + a_{44} + a_{45} + a_{46} \).Finally for \( i = 5 \), calculate: \( \sum_{j=2}^{6} a_{5j} = a_{52} + a_{53} + a_{54} + a_{55} + a_{56} \).
04

Combine All Terms

Combine all the expanded terms from each inner sum:\[ a_{32} + a_{33} + a_{34} + a_{35} + a_{36} + a_{42} + a_{43} + a_{44} + a_{45} + a_{46} + a_{52} + a_{53} + a_{54} + a_{55} + a_{56}. \]These 15 terms represent the full expansion of the double summation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Notation
To make sense of the double summation, one must first understand matrix notation. Matrices are often used to organize numbers, symbols, or expressions in rows and columns, forming a rectangular array. For example, in matrix notation, the term \( a_{ij} \) refers to an element located in the \( i \)-th row and \( j \)-th column of this array. Each pair of indices \( (i, j) \) pinpoints a specific location in the matrix.
This notation helps in clearly arranging data, especially for computational purposes. In the context of our double summation, each \( a_{ij} \) represents a unique element that we need to sum over, between specific row and column indices. This is crucial for visualization and correctly performing the summation.
Inner-Outer Sum Expansion
A double summation can often seem overwhelming, but breaking it down through inner-outer sum expansion eases the process significantly. Here, we have two sums: the inner sum and the outer sum.
  • The outer sum iterates over the variable \( i \), covering the indices from 3 to 5. This means we handle one row of this conceptual matrix at a time.
  • The inner sum iterates over \( j \), from 2 to 6, computing the sum within a specific row. This involves collecting elements along a row for each fixed \( i \).
When processing the double summation, you start with the outer sum. Choose a fixed value of \( i \) to handle all its corresponding inner sums. This will make the matrix processing much more manageable, allowing you to process column by column within each row.
Summation Bounds
Understanding summation bounds is vital in correctly performing and expanding any summation. In our exercise, bounds indicate the range of indices that we include in our sum calculations.
For the double summation \( \sum_{3 \leq i \leq 5, 2 \leq j \leq 6} a_{ij} \):
  • \( 3 \leq i \leq 5 \) suggests that \( i \) spans from 3 to 5 inclusive, setting the bounds for the outer sum. It means you handle the third, fourth, and fifth \( i \)-indices or rows.
  • \( 2 \leq j \leq 6 \) stipulates that \( j \) spans from 2 to 6 inclusive within each selected \( i \), defining bounds for the inner sum. For each row chosen by \( i \), move along the second to the sixth columns.
Grasping these bounds ensures that you cover every element needed in the matrix exactly once, avoiding oversights or duplications in your sum.

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Most popular questions from this chapter

Sei \(X\) eine \(n\)-elementige Menge. (a) Geben Sie eine bijektive Abbildung der Menge aller binären Folgen der Länge \(n\) auf die Menge aller Teilmengen von \(X\) an. (b) Geben Sie damit einen neuen Beweis für die Tatsache \(\mid \mathbf{P}(X) \|=2^{n}\) an.

Zeigen Sie den Satz über die Bijektivität invertierbarer Abbildungen: Sei \(f: X \rightarrow Y\) eine Abbildung. Wenn es eine Abbildung \(f^{\prime}: Y \rightarrow X\) gibt, so dass gilt $$ f \circ f^{\prime}=\operatorname{id}_{Y} \text { und } f^{\prime} \circ f=\mathrm{id}_{X} $$ dann ist \(f\) bijektiv.

Wie viele Folgen \(\left(a_{1}, a_{2}, \ldots, \mathrm{a}_{\mathrm{n}}\right)\) der Länge \(n\) gibt es, wenn die einzelnen Folgenglieder \(a_{i}\) jeweils genau \(q\) Werte annehmen können?

Eine binäre Folge ist eine Folge, deren Elemente nur 0 und 1 sind. Besteht eine solche Folge aus \(n\) Komponenten, so spricht man von einer binären Folge der Länge \(n\). Wie gro \(ß\) ist die Anzahl der binären Folgen der Länge \(n\) ? [Hinweis: Wenn Sie das nicht schnell sehen, schreiben Sie alle binären Folgen der Längen 2 und 3 auf; dann erhalten Sie eine Vermutung, die Sie dann „nur noch" beweisen müssen.]

(a) Zeigen Sie, dass in der gewöhnlichen euklidischen Ebene folgendes gilt: Wenn drei Punkte einer Geraden \(g\) den gleichen Abstand zu einer Geraden \(g^{\prime}\) haben, so haben alle Punkte von \(g\) den gleichen Abstand von \(g^{\prime}\). (b) Seien \(g\) und \(g^{\prime}\) zwei Geraden der gewöhnlichen euklidischen Ebene, die nicht parallel sind. Zeigen Sie, dass es zwei Punkte von \(g\) gibt, die den gleichen \(\mathrm{Ab}\) stand zu \(g^{\prime}\) haben

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