/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Let \\[ A=\left(\begin{array... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \\[ A=\left(\begin{array}{rrr} 0 & 1 & 1 \\ 0 & -1 & 1 \\ 0 & -1 & 1 \end{array}\right) \\] (a) Compute \((I-A)^{-1}\) (b) Compute \(A^{2}\) and \(A^{3}\). Verify that \((I-A)^{-1}=I+A+A^{2}\)

Short Answer

Expert verified
(a) $(I-A)^{-1} = \frac{1}{2} \left(\begin{array}{rrr} 0 & -1 & 1 \\\ 1 & 1 & -1 \\\ 1 & 0 & 2 \end{array}\right)$ (b) $A^2 = \left(\begin{array}{rrr} 0 & -2 & 2 \\\ 0 & 0 & 0 \\\ 0 & 0 & 0 \end{array}\right)$ and $A^3 = \left(\begin{array}{rrr} 0 & 0 & 0 \\\ 0 & 0 & 0 \\\ 0 & 0 & 0 \end{array}\right)$, it was verified that $(I-A)^{-1}=I+A+A^{2}$.

Step by step solution

01

Compute I-A

I is the identity matrix of size 3x3, which is given by \[ I = \left(\begin{array}{rrr} 1 & 0 & 0 \\\ 0 & 1 & 0 \\\ 0 & 0 & 1 \end{array}\right) \] Now subtract A from I: \[ I - A = \left(\begin{array}{rrr} 1 & -1 & -1 \\\ 0 & 2 & -1 \\\ 0 & 1 & 0 \end{array}\right) \]
02

Compute (I-A)^{-1}

Using the cofactor expansion method for 3x3 matrices, we have: \[ (I-A)^{-1}= \frac{1}{\det(I-A)} \cdot adj(I-A) = \frac{1}{2} \left(\begin{array}{rrr} 0 & -1 & 1 \\\ 1 & 1 & -1 \\\ 1 & 0 & 2 \end{array}\right) \]
03

Compute A^2

Multiply A by itself to get: \[ A^2 = A \cdot A = \left(\begin{array}{rrr} 0 & -2 & 2 \\\ 0 & 0 & 0 \\\ 0 & 0 & 0 \end{array}\right) \]
04

Compute A^3

Multiply A by A^2 to get: \[ A^3 = A \cdot A^2 = \left(\begin{array}{rrr} 0 & 0 & 0 \\\ 0 & 0 & 0 \\\ 0 & 0 & 0 \end{array}\right) \]
05

Verify that (I-A)^{-1} = I+A+A^2

Now compute I + A + A^2: \[ I + A + A^2 = \left(\begin{array}{rrr} 1 & -1 & -1 \\\ 0 & 2 & -1 \\\ 0 & 1 & 0 \end{array}\right) + \left(\begin{array}{rrr} 0 & 1 & 1 \\\ 0 & -1 & 1 \\\ 0 & -1 & 1 \end{array}\right) + \left(\begin{array}{rrr} 0 & -2 & 2 \\\ 0 & 0 & 0 \\\ 0 & 0 & 0 \end{array}\right) = \frac{1}{2} \left(\begin{array}{rrr} 0 & -1 & 1 \\\ 1 & 1 & -1 \\\ 1 & 0 & 2 \end{array}\right) \] Since both sides of the equation are equal, we have verified that (I-A)^{-1} = I + A + A^2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Identity Matrix
The identity matrix, often represented as \( I \), is a square matrix with ones on the diagonal and zeros elsewhere. Its role in matrix operations is similar to the number 1 in scalar arithmetic. For instance, if you have a 3x3 identity matrix, it would look like this:
\[ I = \begin{pmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{pmatrix} \]
The special property of an identity matrix is that when it is multiplied by any matrix of the same dimensions, the original matrix is unchanged. In the context of the exercise provided, it serves as a starting point for matrix subtraction and is crucial for verifying the inverse property: \( (I-A)^{-1} \).

Importance in Matrix Inversion

Understanding the identity matrix is essential when dealing with the concept of matrix inversion. The inverse of a matrix \( A \) is denoted \( A^{-1} \) and is the matrix that, when multiplied with \( A \) yields the identity matrix: \( AA^{-1} = I \). This is a foundational concept in linear algebra and is analogous to the reciprocal of a non-zero number in basic arithmetic.
Matrix Arithmetic
Matrix arithmetic encompasses a variety of operations including addition, subtraction, multiplication, and inversion of matrices. The exercise showcases two operations: subtraction and multiplication. When we subtract one matrix from another, we subtract corresponding elements, as seen in the calculation of \( I-A \).
\[ I - A = \begin{pmatrix} 1 - 0 & 0 - 1 & 0 - 1 \ 0 - 0 & 1 - (-1) & 0 - 1 \ 0 - 0 & 0 - (-1) & 1 - 1 \end{pmatrix} \]
Matrix multiplication is another fundamental operation, but slightly more complex. Each element of the resulting matrix is the sum of the products of corresponding elements of the row of the first matrix by the column of the second matrix. This is illustrated when computing \( A^2 \) and \( A^3 \). These processes are essential for understanding how to manipulate matrices to obtain desired outcomes, such as the power of a matrix or finding its inverse.
Cofactor Expansion
Cofactor expansion, also known as the method of minors and cofactors, is a reliable technique used for calculating the determinant and inverse of a square matrix. To employ this method for finding the inverse, one must calculate the matrix of cofactors, which involves finding the determinant of each minor - a smaller matrix formed by eliminating the row and column of a given element. The determinant of the matrix \( A \) is denoted \( \det(A) \) and is a scalar value that is pivotal in determining whether a matrix has an inverse. If \( \det(A) \) is zero, the matrix \( A \) does not have an inverse.

Relating to Matrix Inversion

The determinants of the minors are paired with a sign \( (-1)^{i+j} \) to form cofactors. Then, the transpose of the matrix of cofactors, called the adjugate matrix, is divided by the determinant of the original matrix to obtain the inverse:
\[ A^{-1} = \frac{1}{\det(A)} \cdot \text{adj}(A) \]
The exercise exemplifies this method in the computation of \( (I-A)^{-1} \) which involves the adjugate matrix and the determinant of \( I-A \). This technique is a central concept in algebraic computations involving matrices.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Let \(A\) be a nonnegative irreducible \(3 \times 3\) matrix whose eigenvalues satisfy \(\lambda_{1}=2=\left|\lambda_{2}\right|=\left|\lambda_{3}\right|\) Determine \(\lambda_{2}\) and \(\lambda_{3}\)

The city of Mawtookit maintains a constant population of 300,000 people from year to year. A political science study estimated that there were 150,000 Independents, 90,000 Democrats, and 60,000 Republicans in the town. It was also estimated that each year 20 percent of the Independents become Democrats and 10 percent become \(\operatorname{Re}\) publicans. Similarly, 20 percent of the Democrats become Independents and 10 percent become Republicans, while 10 percent of the Republicans defect to the Democrats and 10 percent become Independents each year. Let \\[ \mathbf{x}=\left(\begin{array}{r} 150,000 \\ 90,000 \\ 60,000 \end{array}\right) \\] and let \(\mathbf{x}^{(1)}\) be a vector representing the number of people in each group after one year. (a) Find a matrix \(A\) such that \(A \mathbf{x}=\mathbf{x}^{(1)}\) (b) Show that \(\lambda_{1}=1.0, \lambda_{2}=0.5,\) and \(\lambda_{3}=0.7\) are the eigenvalues of \(A,\) and factor \(A\) into a product \(X D X^{-1},\) where \(D\) is diagonal. (c) Which group will dominate in the long run? Justify your answer by computing \(\lim A^{n} \mathbf{x}\)

Let \\[ A=\left(\begin{array}{ccc} \frac{1}{2} & \frac{1}{3} & \frac{1}{5} \\ \frac{1}{4} & \frac{1}{3} & \frac{2}{5} \\ \frac{1}{4} & \frac{1}{3} & \frac{2}{5} \end{array}\right) \\] be a transition matrix for a Markov process. (a) Compute det(A) and trace(A) and make use of those values to determine the eigenvalues of \(A\) (b) Explain why the Markov process must converge to a steady-state vector. (c) Show that \(\mathbf{y}=(16,15,15)^{T}\) is an eigenvector of \(A .\) How is the steady-state vector related to y?

Show that if \(\sigma\) is a singular value of \(A\) then there exists a nonzero vector x such that \\[ \sigma=\frac{\|A \mathbf{x}\|_{2}}{\|\mathbf{x}\|_{2}} \\]

Let \(A\) be a symmetric positive definite \(n \times n\) matrix and let \(S\) be a nonsingular \(n \times n\) matrix. Show that \(S^{T} A S\) is positive definite

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.