Chapter 2: Problem 11
Show that if \(A\) is singular, then adj \(A\) is also singular.
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Chapter 2: Problem 11
Show that if \(A\) is singular, then adj \(A\) is also singular.
These are the key concepts you need to understand to accurately answer the question.
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Let \(A\) and \(B\) be \(2 \times 2\) matrices (a) \(\operatorname{Does} \operatorname{det}(A+B)=\operatorname{det}(A)+\operatorname{det}(B) ?\) (b) \(\operatorname{Does} \operatorname{det}(A B)=\operatorname{det}(A) \operatorname{det}(B) ?\) (c) \(\operatorname{Does} \operatorname{det}(A B)=\operatorname{det}(B A) ?\) Justify your answers.
Consider the \(3 \times 3\) Vandermonde matrix \\[ V=\left(\begin{array}{lll} 1 & x_{1} & x_{1}^{2} \\ 1 & x_{2} & x_{2}^{2} \\ 1 & x_{3} & x_{3}^{2} \end{array}\right) \\] (a) Show that \(\operatorname{det}(V)=\left(x_{2}-x_{1}\right)\left(x_{3}-x_{1}\right)\left(x_{3}-x_{2}\right)\) Hint: Make use of row operation III. (b) What conditions must the scalars \(x_{1}, x_{2},\) and \(x_{3}\) satisfy in order for \(V\) to be nonsingular?
Show that if \(A\) is nonsingular, then adj \(A\) is nonsingular and \\[ (\operatorname{adj} A)^{-1}=\operatorname{det}\left(A^{-1}\right) A=\operatorname{adj} A^{-1} \\]
Prove that if a row or a column of an \(n \times n\) matrix \(A\) consists entirely of zeros, then \(\operatorname{det}(A)=0\).
Use mathematical induction to prove that if \(A\) is an \((n+1) \times(n+1)\) matrix with two identical rows, then \(\operatorname{det}(A)=0\).
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