/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Let \(\left\\{\mathbf{u}_{1}, \m... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(\left\\{\mathbf{u}_{1}, \mathbf{u}_{2}\right\\}\) be an orthonormal basis for \(\mathbb{C}^{2},\) and let \(\mathbf{z}=(4+2 i) \mathbf{u}_{1}+(6-5 i) \mathbf{u}_{2}\) (a) What are the values of \(\mathbf{u}_{1}^{H} \mathbf{z}, \mathbf{z}^{H} \mathbf{u}_{1}, \mathbf{u}_{2}^{H} \mathbf{z},\) and \(\mathbf{z}^{H} \mathbf{u}_{2} ?\) (b) Determine the value of \(\|\mathbf{z}\|\)

Short Answer

Expert verified
In summary, we find the Hermitian inner products as follows: \(\mathbf{u}_{1}^{H} \mathbf{z} = 4 + 2i \) \(\mathbf{z}^{H} \mathbf{u}_{1} = 4 - 2i \) \(\mathbf{u}_{2}^{H} \mathbf{z} = 6 - 5i \) \(\mathbf{z}^{H} \mathbf{u}_{2} = 6 + 5i \) And the value of the norm of the vector \(\mathbf{z}\) is \(\|\mathbf{z}\| = \sqrt{70}\).

Step by step solution

01

Write down given expressions for the problem

We are given the orthonormal basis \(\left\\{\mathbf{u}_{1}, \mathbf{u}_{2}\right\\}\) for \(\mathbb{C}^{2}\), and the vector \(\mathbf{z}\) is expressed as follows: \[ \mathbf{z} = (4 + 2i)\mathbf{u}_1 + (6 - 5i)\mathbf{u}_2 \] We need to find the values of: \[ \mathbf{u}_{1}^{H} \mathbf{z}, \mathbf{z}^{H} \mathbf{u}_{1}, \mathbf{u}_{2}^{H} \mathbf{z}, \text{ and } \mathbf{z}^{H} \mathbf{u}_{2} \] and also determine the value of \(\|\mathbf{z}\|\).
02

Use orthonormal system properties to find the inner products

Since \(\left\\{\mathbf{u}_{1}, \mathbf{u}_{2}\right\\}\) is an orthonormal basis, we have the following properties: \[ \mathbf{u}_1^{H}\mathbf{u}_1 = \mathbf{u}_2^{H}\mathbf{u}_2 = 1 \\ \mathbf{u}_1^{H}\mathbf{u}_2 = \mathbf{u}_2^{H}\mathbf{u}_1 = 0 \] Now we can compute the inner products: \[ \mathbf{u}_{1}^{H} \mathbf{z} = \mathbf{u}_1^{H}[(4 + 2i)\mathbf{u}_1 + (6 - 5i)\mathbf{u}_2] = (4 + 2i)\mathbf{u}_1^{H}\mathbf{u}_1 + (6 - 5i)\mathbf{u}_1^{H}\mathbf{u}_2 = 4 + 2i \] In a similar way, we can calculate the other inner products: \[ \mathbf{z}^{H} \mathbf{u_1} = [(4 - 2i)\mathbf{u}_1 + (6 + 5i)\mathbf{u}_2]^{H}\mathbf{u}_1 = (4 -2i) \] \[ \mathbf{u}_{2}^{H} \mathbf{z} = \mathbf{u}_1^{H}[(4 + 2i)\mathbf{u}_1 + (6 - 5i)\mathbf{u}_2] = (4 + 2i)\mathbf{u}_2^{H}\mathbf{u}_1 + (6 - 5i)\mathbf{u}_2^{H}\mathbf{u}_2 = 6 - 5i \] \[ \mathbf{z}^{H} \mathbf{u_2} = [(4 - 2i)\mathbf{u}_1 + (6 + 5i)\mathbf{u}_2]^{H}\mathbf{u}_2 = 6 + 5i \] In conclusion, we have found the Hermitian inner products as follows: \[ \mathbf{u}_{1}^{H} \mathbf{z} = 4 + 2i \\ \mathbf{z}^{H} \mathbf{u}_{1} = 4 - 2i \\ \mathbf{u}_{2}^{H} \mathbf{z} = 6 - 5i \\ \mathbf{z}^{H} \mathbf{u}_{2} = 6 + 5i \]
03

Determine the norm of the vector \(\mathbf{z}\)

The norm of a vector \(\mathbf{z}\) in an orthonormal basis is given by: \[ \|\mathbf{z}\| = \sqrt{\mathbf{z}^{H}\mathbf{z}} \] So we need to find the value of \(\mathbf{z}^{H}\mathbf{z}\): \[ \mathbf{z}^{H}\mathbf{z} = [(4 - 2i)\mathbf{u}_1 + (6 + 5i)\mathbf{u}_2]^H[(4 + 2i)\mathbf{u}_1 + (6 - 5i)\mathbf{u}_2] \] Using the properties of the Hermitian inner product and the orthonormal basis, we have: \[ \mathbf{z}^{H}\mathbf{z} = (4 - 2i)(4 + 2i) + (6 + 5i)(6 - 5i) = 20 + 50 = 70 \] Now we can find the norm of \(\mathbf{z}\): \[ \|\mathbf{z}\| = \sqrt{\mathbf{z}^{H}\mathbf{z}} = \sqrt{70} \] So the value of the norm of the vector \(\mathbf{z}\) is \(\sqrt{70}\).

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Most popular questions from this chapter

Let \(A\) be an \(n \times n\) matrix with singular value decomposition \(U \Sigma V^{T}\) and let \\[ B=\left(\begin{array}{cc} O & A^{T} \\ A & O \end{array}\right) \\] Show that if \\[ \mathbf{x}_{i}=\left(\begin{array}{c} \mathbf{v}_{i} \\ \mathbf{u}_{i} \end{array}\right], \quad \mathbf{y}_{i}=\left[\begin{array}{r} -\mathbf{v}_{i} \\ \mathbf{u}_{i} \end{array}\right], \quad i=1, \ldots, n \\] then the \(\mathbf{x}_{i}\) 's and \(\mathbf{y}_{i}\) 's are eigenvectors of \(B\). How do the eigenvalues of \(B\) relate to the singular values of \(A ?\)

Show that \(A\) and \(A^{T}\) have the same nonzero singular values. How are their singular value decompositions related?

It follows from Exercise 14 that, for a diagonalizable matrix, the number of nonzero eigenvalues (counted according to multiplicity) equals the rank of the matrix. Give an example of a defective matrix whose rank is not equal to the number of nonzero eigenvalues.

Which of the matrices that follow are Hermitian? Normal? (a) \(\left(\begin{array}{cc}1-i & 2 \\ 2 & 3\end{array}\right)\) (b) \(\left(\begin{array}{cc}1 & 2-i \\ 2+i & -1\end{array}\right)\) \((\mathrm{c})\left(\begin{array}{cc}\frac{1}{\sqrt{2}} & -\frac{1}{\sqrt{2}} \\\ \frac{1}{\sqrt{2}} & \frac{1}{\sqrt{2}}\end{array}\right)\) (d) \(\left(\begin{array}{cc}\frac{1}{\sqrt{2}} i & \frac{1}{\sqrt{2}} \\\ \frac{1}{\sqrt{2}} & -\frac{1}{\sqrt{2}} i\end{array}\right)\) (e) \(\left(\begin{array}{ccc}0 & i & 1 \\ i & 0 & -2+i \\ -1 & 2+i & 0\end{array}\right)\) (f) \(\left(\begin{array}{ccc}3 & 1+i & i \\ 1-i & 1 & 3 \\ -i & 3 & 1\end{array}\right)\)

Let \(A\) be an \(n \times n\) symmetric negative definite \(\mathrm{ma}-\) trix. (a) What will the sign of det( \(A\) ) be if \(n\) is even? If \(n\) is odd? (b) Show that the leading principal submatrices of \(A\) are negative definite. (c) Show that the determinants of the leading principal submatrices of \(A\) alternate in sign.

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