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Find singular value decompositions for the matrices listed in Exercises 7 through 14. Work with paper and pencil. In each case, draw a sketch analogous to Figure 4 in the text, showing the effect of the transformation on the unit circle, in three steps.

Short Answer

Expert verified

A singular value decomposition of A is given by

Step by step solution

01

To find the singular values of A

Given that,

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Now the singular values of A are found by first computing the eigenvalues of the square matrix

Then:

Let characteristic polynomial ofbe p(x). Then:

Thus the characteristic polynomial isThis implies that the roots of p(x) are 1,4 . Hence the eigenvalues ofareandThus the singular values of A areand

Now let

X1 = x1

x2

be an eigenvector corresponding to the eigenvalue 4. Therefore (AtA)X1=4X1which means (4I2-AtA)X1=0. From this equation we get that

Therefore

3x1= 0

This implies that x1= 0.

Therefore is an eigenvector corresponding to the eigenvalue 4 for any non-zero real number r. By putting r=1, we conclude that is an eigenvector corresponding to the eigenvalue 4. Thus, is a unit eigenvector of corresponding to the eigenvalue

02

To find the singular value decomposition of A

Now let

be an eigenvector corresponding to the eigenvalue 1 . Thereforewhich meansFrom this equation we get that

Therefore,.

This implies that

Therefore.

is an eigenvector corresponding to the eigenvalue 1 for any non-zero real number r. By putting r=1, we conclude that.

is an eigenvector corresponding to the eigenvalue 1. Thusis a unit eigenvector ofcorresponding to the eigenvalue

Hence we have:

The singular values of A areand

Thus

Now to find U, we compute the columns and of U as follows:

Thus

Therefore, a singular value decomposition of A is then given by

03

Image of the unit circle

The image of the unit circle has the following form:

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