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If the singular values of an n×nmatrix A are all 1 , A is necessarily orthogonal?

Short Answer

Expert verified

Use the fact thatAtA is diagonalizable

Step by step solution

01

To finding A necessarily orthogonal for value of an matrix A

Let A be an n×nmatrix such that the singular values of A are all 1. This implies that, all the eigenvalues of the matrixAtA are 1.

Note that, AtAis a symmetric matrix since AtAt=AtAtt=AtA.HenceAtA is diagonalizable. Thus, there exists a diagonal matrixand an invertible matrix P such that

AtA=PDP-1

02

To finding A necessarily orthogonal for value of an matrix A

Also, from the construction of D , we know that the diagonal entries of D are basically the eigenvalues of AtA.

Here, all the eigenvalues of the matrix AtAare 1. This shows that all the diagonal entries of D are 1. Hence D=In. Using this we get that,

AtA=PDP-1=PInP-1=PP-1=In

Hence AtA=Inwhich implies that A is orthogonal.

03

Step 3:Final proof

Use the fact that AtAis diagonalizable.

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