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Consider an n×mmatrix Aof rank r , and a singular value decomposition A=U∑vTExplain how you can express the least-squares solutions of a system Ax→=b→as linear combinations of the columns role="math" localid="1660733836229" v→1....,v→m of V

Short Answer

Expert verified

x=∑i-1myiUi

Step by step solution

01

To explaining the least-squares solutions of a system Ax→=b→ as linear combinations of the columns v→1,...,v→m  of  V

A - n×mmatrix

A=U∑V· ···(Singular value decomposition)

RankA=r . Sis are singular values. Denote,

∑-1=S1-1Sr-100

Now, x is a least-squares solution to

Ax=b

if and only if xis a solution of

A·Ax=A·b.Now,

A·A=V∑U·U∑V·=V∑2VT

02

To explaining the least-squares solutions of a system  Ax→=b→ as linear combinations of the columns  v→1,...v→m of  V

So, we have

V∑2V·x=U∑V·b·b⇒V∑V·2x=∑U·b(Multiplybothsides⇒V·x=∑-1U·b⇒x=V∑-1U·b...call∑-1U·b=y=y1...,ym·,then,x=∑i-1myiUi

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