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Prove Theorem 3.3.4d: If 鈥榤鈥 vectors spans an m-dimensional space, they form a basis of the space.

Short Answer

Expert verified

If 鈥榤鈥 vectors spans an m-dimensional space, they form a basis of the space.

Step by step solution

01

To prove the given statement

Let V be a vector space of dimension 鈥榤鈥

Let us consider a set G consisting of 鈥榤鈥 vectors such that G is a finite generating set for V. Then by theorem, 鈥淚f a vector space V is generated by a finite set S , then some subset of S is a basis for V and hence, V has a finite basis鈥, some subset H of G is a basis for V. Now by theorem, 鈥淚f V be a vector space having a finite basis, then every basis for V contains the same number of vectors鈥. This implies that the subset H of G contains exactly 鈥榤鈥 vectors.

Since a subset H of G contains 鈥榤鈥 vectors then G must contains at least 鈥榤鈥 vectors.

Moreover, if G contains exactly 鈥榤鈥 vectors then we must have H=G, so that G is a basis for the vector space V.

02

   Final Answer

Since the generating set G of vector space contains at least 鈥榤鈥 vectors, therefore, we need at least 鈥榤鈥 vectors to span a space of dimension 鈥榤鈥. If G contains exactly 鈥榤鈥 vectors then we must have H=G, so that G is a basis for the vector space V.

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