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Verify that the kernel of a linear transformation is closed under addition and scalar multiplication. See Theorem 3.1.6.

Short Answer

Expert verified

The kernel of a linear transformation is closed under addition and scalar multiplication.

Step by step solution

01

Step 1: Objective

The objective is to verify that the kernel of a linear transformation is closed under addition and scalar multiplication.

02

Proving kernel of T is closed under addition

ConsiderthelineartransformationT(x)=Ax,fromRmtoRn,wherexisinRmandAxisinRn.Letx1"andx2"bethekernelofT.ThenT(x1)=0andT(x2)=0.T(x1+x2)=T(x1)+T(x2)=0+0=0So,x1+x2isinthekernelofT.Hence,thekernelofTisclosedunderaddition.

03

Proving kernel of T is closed under multiplication

Letx1beinthekernelofTandkR.ThenT(x1)=0.T(kx1)=kT(x1)=k0=0So,kxisinthekernelofT.Hence,thekernelofTisclosedunderscalarmultiplication.

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