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Consider a subspace V inm that is defined by homogeneous linear equations

|a11x1+a12x2++a1mxm=0a21x1+a22x2++a2mxm=0鈥夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌鈥夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌鈥夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆鈥夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌an1x1+a22x2++anmxm=0|.

What is the relationship between the dimension of Vand the quantitym-n

? State your answer as an inequality. Explain carefully.

Short Answer

Expert verified

A subspaceV of mhas dimension at least mn.

Step by step solution

01

To mention given data and recall the theorem 3.3.7

We have the subspaceV ofm defined byn homogeneous linear eqautions,

role="math" localid="1660126682574" a11x1+a12x2++a1mxm=0a21x1+a22x2++a2mxm=0鈥夆赌夆赌夆赌夆赌夆赌夆赌夆赌鈥夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆夆夆鈥夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌鈥夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆an1x1+an2x2++anmxm=0,

Therefore,V can be written as

V=ker(A), whereA is annm matrixA=[aij] .

Suppose the column vector bex1x2xm .

Theorem 3.3.7, is stated as follows:

For anynm matrix A, the equation,

dim(ker(A))+dim(im(A))=m.

02

To find the relationship between the dimension V and m-n 

We have the rank of Arank(A)n.

Thus, by Theorem 3.3.7, we have,

dim(V)=dim(ker(A))=mrank(A)mn

dim(V)mn

.

Hence, a subspace Vofm has dimension at least mn.

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