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In Exercises 25 through 30 , find the matrix B of the linear transformation T(x)=Ax with respect to the basisJ=(v1,..,vm).

A=[-1100-223-96];v1=[111];v2=[123;v3=136]

Short Answer

Expert verified

The matrix is, B=000010002.

Step by step solution

01

Consider the vectors.

The matrix and vectors are,

A=[-1100-223-96];v1=[111];v2=[123];v3=[136]

02

Compute the matrix using formula.

The formula is, B=S-1AS.

Compute the matrix and the inverse of S.

S=v1,v2,v3=111123136S-1=113-31-35-21-21

Substitute these values in the formula.

B=S-1ASB=113-31-35-21-21-1100-223-96111123136B=000010002

03

Final answer.

The matrix is, B=000010002.

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