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Find the angleθbetween each of the pairs of vectors u→and localid="1659433601917" v→in exercises 4 through

6.u→=[1-12-2,v→=2345]

Short Answer

Expert verified

The angle θbetween u→and v→is about 97.4°.

Step by step solution

01

Angle between two vectors

Consider two nonzero vectors x→and y→in Rn. The anglebetween these vectors

Is defined as:

θ=arccos(θ)=x→.y→||x→||.||y→||

02

Substitute the values into the angle formula

The given vectors are u→=1-12-2and v→=2345.

Now, calculate the angle by substituting the required values into the angle formula

θ=arccos(θ)=u→.v→||u→||.||v→||.

localid="1659428200763" θ=arccos(θ)=u→.v→||u→||.||v→||=arccos(θ)1-12-2.234512+(-1)2+22+(-2)122+32+42+52=arccos(θ)1.2-1.3+2.4-2.51+1+4+44+9+16+25=arccos(θ)2-3+8-1010.54=arccos(θ)-3540≈97.4°

Hence, the value ofθis about 97.4°.

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