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Consider an mn matrix A withKer(A)={0}. Show that there exists annm matrix B such thatBA=ln.

Short Answer

Expert verified

The matrix is ATA-1-AT.

Step by step solution

01

Determine the matrix R.

Consider amn matrix A.

If Ker(A)={0} for arole="math" localid="1659500428667" mn matrix A then the matrix A is invertible.

If the matrix A is invertible then the matrixrole="math" localid="1659500442729" AT is invertible.

If the matrices A and B is invertible then the matrix AB is invertible.

As the value of Ker(A)={0}, by the definition the matrix A is invertible.

By the definition, the matricesAT andATA are invertible.

Assume the matrix BA=ATA-1, simplify the matrix BA as follows.

BA=A-1lnA=A-1AT-1ATA=A-1AT-1ATABA=A-1lnA

Further, simplify the equation as follows.

BA=A-1lnA=A-1ABA=ln

Hence, for the matrixB=ATA-1-AT the equation BA=ln.

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