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In Exercises 55 through 64, find all matricesX that satisfy the given matrix equation.

123012X=l2

Short Answer

Expert verified

The matrix X that will satisfy the equation will be 1+ef-2-2e1-2fef, where are constants.

Step by step solution

01

Assuming the matrix

Since, the product of matrix23and matrix X gives the matrix of order22then the order of matrix X should be32.

Let the matrix beX=abcdef.

Then the equation will become

role="math" 123012abcdef=1001

02

Solving the Matrix

To solve the given matrix equation, first simplify the left-hand side matrix.

a+2c+3eb+2d+3fc+2ed+2f=1001

Now equating the left-hand and right-hand matrix.

a+2c+3e=1b+2d+3f=0c+2e=0d+2f=1

On solving the above equations, we will get

data-custom-editor="chemistry" a=1+e,b=f-2,c=-2e,d=1-2f,e=e,f=f

Hence, the matrix X which satisfied the given equation, is 1+ef-2-2e1-2fef, where are constants.

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