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For which values of the constant k is the following matrix invertible?

[11112k14k2]

Short Answer

Expert verified

For each kdistinct than 1 or 2.

Step by step solution

01

Check the given matrix is invertible or not

The given matrix will be invertible if and only if its reduced row echelon form is l3. Therefore, let transform the given matrix by using the row operation

11112k14k2R2R2-R1,R3R3-R111101k-103k2-1R3R3-3Rz11101k-100k2-3k+2

It is clear know that reduced row echelon form of the given matrix will be except for solutions of the equations

k2-3k+2=0

02

Find the value of k

Because in that case the entries of third row are all .Therefore, rewriting the left side of the equation as,

k2-3k+2=k2-2k-k+2=k(k-2)-(k-2)=(k-2)(k-1)

We obtain that its solution is role="math" localid="1660369236997" k=1andk=2.

Hence, the given matrix is invertible for each kexcept k=1andk=2.

For each distinct than or 2.

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