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Do the polynomials f(t)=1+2t+9t2+t3,g(t)=1+7t+7t3,h(t)=1+8t+t2+5t3,andk(t)=1+8t+4t2+8t3

form a basis ofP3?

Short Answer

Expert verified

The solution is the given polynomials forms the basis ofP3

Step by step solution

01

Definition for the linear independent.

If f is redundant if it is a linear combination off1,f2,...,fi-1then the elementsf1,f2,...,fnare linearly independent.

In this case the equation becomes

c1f1+c2f2+...+cnfn=0

Only has trivial solution

.c1=c2=....=cn=0

02

Solution for the polynomials of basis

Consider the given polynomial as follows

f(t)=1+2t+9t2+t3

g(t)=1+7t+7t3

h(t)=1+8t+t2+5t3

k(t)=1+8t+4t2+8t3

Here the simplification becomes as follows

f(t)+g(t)+h(t)+k(t)=(1+1+1+1)t3+(9+0+1+4)t2+(2+7+8+8)t+(1+1+1+1)鈥夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌夆赌=4t3+14t2+25t+4

Since, the polynomial of the basis is of degree equal to 3.

Therefore, the given polynomial forms the basis of P3.

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