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Find the basis of all Pn, and determine its dimension.

Short Answer

Expert verified

The dimension of Pn is n+1which is spanned by role="math" localid="1659419285127" Span1,t,t2,...,tn.

Step by step solution

01

Determine the span

Consider the set of all polynomial Pn.

The set role="math" localid="1659419586773" {1,t,t2,...,tn}is linear independent set of Vif there exist constantai∈R such that a0+a1t1+a2t2+...+antn=0wherea0=a1=a2=...=an=0 .

Any polynomial ft∈Pn is defined as follows.

f(t)=b0+b1t+b2t2+...+bntn

02

Compare the polynomials

Compare the equationsb0+b1t+b2t2+...+bntn=0 bot side as follows.

b0+b1t+b2t2+...+.+bntn=0b0+b1t+b2t2+...+.+bntn=(0)+0t+0t2+...+0tnbi=0

By the definition of linear independence, the subset 1,t,t2,...,tnis L.I where are linear independent.

Therefore, the set of polynomialPn is spanned by Span1,t,t2,...,tn.

Hence, the dimension ofAis and n+1spanned bySpan1,t,t2,...,tn.

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