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Find the basis of each of the space V=Rmn, and determine its dimension.

Short Answer

Expert verified

The dimension of a mnmatrix is mn which is spanned byrole="math" localid="1659418617501" span100000000,000010000,000100000.,,.000000001 .

Step by step solution

01

Determine the matrix.

Consider the matrixA=a11a12a1na21a22a2nam1am2amn whereaij are real.

Simplify the equation A=a11a12a1na21a22a2nam1am2amnas follows.

role="math" localid="1659418385609" A=a11a12a1na21a22a2nam1am2amnA=a1100000000+0000a220000+000a2100000+..+00000000amnA=a11100000000+a22000010000+a21000100000+..+amn000000001

02

Find the basis of each required space

In the matrix A,100000000,000010000,000100000.,,.000000001are linear independent.

Therefore, the matrix A is spanned by span100000000,000010000,000100000.,,.000000001.

Hence, the dimension of A is mn and spanned by span100000000,000010000,000100000.,,.000000001.

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