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Find the basis of each of the spaceV=R32,and determine its dimension.

Short Answer

Expert verified

The dimension of a32 matrix is 6 which is spanned byrole="math" localid="1659416482326" Span100000,010000,001000,000100,000010,000001 .

Step by step solution

01

Determine the matrix

Consider the matrix A=a11a12a21a22a31a32where a and b are real.

Simplify the equationA=a11a12a21a22a31a32as follows.

role="math" localid="1659416376950" A=a11a12a21a22a31a32A=a1100000+0a120000+00a21000+a22000a2200+0000a310+00000a32A=a11100000+a12010000+a21001000+a22000100+a31000010+a32000001

02

Find the basis of each required space

In the matrix A=100000,010000,001000,000100,000010and000001are linear independent.

Therefore, the matrix A is spanned by span=100000,010000,001000,000100,000010,000001.

Hence, the dimension of A is 6 and spanned by span=100000,010000,001000,000100,000010,000001.

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