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Question : Find the weights w1,w2,w3 in Exercise 70 for

a1=-1, a2=0, a3=1.Compare this with Simpson's rule in calculus.

Short Answer

Expert verified

The solution is-11ftdt=i=1nwifai

Step by step solution

01

Definition of isomorphism

An invertible linear transformation T is called an isomorphism.

Also says that the linear space V is isomorphic to the linear space W if there exists an isomorphism T from V to W.

02

Step:2 Determination of the invertible matrix

Consider a basis f1,...,fnof Pn-1.

Let a1,...,anbe distinct real numbers.

Consider the n 脳 n matrix M whose ijth entry is fjai.

.Here also given that the value of the weights are a1=-1,a2=0,a3=1

Assume that the basis B=f1,...,fnis the basis of a linear space V then the coordinate transformation LBf=fB from V to Rn is an isomorphism

Now when applying simpson鈥檚 rule in calculus that there exist 鈥渨eights鈥 w1,...,wnsuch that -11ftdt=i=1nwifai.

Here by the properties of the isomorphisms we have that the weights w1,...,wnobtains the function -11ftdt=i=1nwifaifor all the polynomials in Pn-1.

Hence the proof.

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