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Prove part (a) of Theorem 3.4.2.

Short Answer

Expert verified

If Ibe the basis of a subspace V of nthen x鈬赌+y鈬赌I=x鈬赌I+x鈬赌Ifor all vectors x鈬赌andy鈬赌in V.

Step by step solution

01

Given

IfIbe the basis of a subspace V of nthen

x鈬赌+y鈬赌I+y鈬赌I for all vectors in x鈬赌andy鈬赌V.

02

Finding the coordinate vectors of x⇀  and y⇀ 

Let I=v鈬赌1,v鈬赌2,...,v鈬赌nbe the basis of the subspace V ofn

Then any vectors x鈬赌,y鈬赌ncan be uniquely represented as a linear combinations of the vectors v鈬赌1,v鈬赌2,...,v鈬赌n. Then we have

localid="1660645060506" x鈬赌=a1v鈬赌1+a2v鈬赌2+...+anv鈬赌nandy鈬赌=b1v鈬赌1+b2v鈬赌2+...+bnv鈬赌n

localid="1660645555472" x鈬赌I=a1a2...anandy鈬赌I=b1b2...bn

03

Finding the coordinate vectors ofx⇀+y⇀

Since we have

x鈬赌=a1v鈬赌1+a2v鈬赌2+...+anv鈬赌nandy鈬赌=b1v鈬赌1+b2v鈬赌2+...+bnv鈬赌n

Where

x鈬赌+y鈬赌=a1v鈬赌1+a2v鈬赌2+...+anv鈬赌nx鈬赌+b1v鈬赌1+b2v鈬赌2+...+bnv鈬赌n+x鈬赌+y鈬赌=(a1+b1)v鈬赌1+(a2+b2)v鈬赌2+...(an+bn)v鈬赌nx鈬赌+y鈬赌=c1v鈬赌1+c2v鈬赌2+...+cnv鈬赌nWhereci=ai+bi,i=1,2,3,...n.x鈬赌+y鈬赌I=c1c2...cn

04

  To prove [x⇀+y⇀]I=[x⇀]I+[y⇀]I

We have

x鈬赌I=a1a2...anandy鈬赌I=b1b2...bnAndx鈬赌+y鈬赌I=c1c2...cnx鈬赌+y鈬赌I=c1c2...cn=a1a2...an+b1b2...bnx鈬赌+y鈬赌I=x鈬赌I+y鈬赌I

05

  Final Answer

IfI=v鈬赌1,v鈬赌2,...,v鈬赌nbethebasisofasubspaceVofn,thenx鈬赌+y鈬赌I=x鈬赌I+y鈬赌Iforallvectorsx鈬赌andy鈬赌inV.be

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