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Let A be the n×nmatrix with all 1’s on the diagonal and all 0’s above and below the diagonal. What is Ax→ , where x→ is a vector in Rn?

Short Answer

Expert verified

Ax→for a matrix A with all 1’s on the diagonal and all 0’s above and below the diagonal is, Ax→ is,xyz .

Step by step solution

01

Consider the matrix

IfA is an n x m matrix with row vectors Ӭ1→,...Ӭn→ and x→is a vector in Rmthen,

Ax→=[-Ӭ→1-⋮-Ӭn→-]x→[-Ӭ→1.x→-⋮-Ӭn→.x→-]

Let the vector is,

x→=xyz

The matrix A with all 1’s on the diagonal and all 0’s above and below the diagonal is,

100010001

02

Perform the multiplication operation

The system Ax→ is,

role="math" localid="1664201537736" Ax→=100010001xyzAx→=xyz

Hence, xyzis the value of Ax→for the matrix A with all 1’s on the diagonal and all 0’s above and below the diagonal.

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