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Answer the questions posed in Exercise 54 for the system.

|ddt=ddt=-p-q|

where pand qare positive and q2>4p.

Short Answer

Expert verified

(a) The zero state is a stable equilibrium and the sketch of the system is in explanation.

(b) All trajectories converge to origin and it observe that for condition <0door reaches <0.

Step by step solution

01

(a) Obtain equation from the system.

Let the equations from the given determinant are as follows:

ddt=ddt=-p-q

The corresponding matrix for the system is:

A=01-p-q

02

Calculate the Eigen values of given system and sketch of the graph.

Eigen values are given by the characteristic equation

A-I=0-1-p-q-=02+q+p=0=-qq2-4q2,q2>4q

Thus, the Eigen values of are negative.

Hence, zero state is a stable equilibrium.

The phase portrait is as follows:

03

(b) Movement of door for different trajectory.

Let E1, E2are Eigen spaces of 1and role="math" localid="1665036517865" 2. Since both eigenvalues are negative.

Hence, the solution is:

xt=C1e1tv1+C2e2tv2

Here, the values are x=, role="math" localid="1665035976107" v1corresponding to 1=-q-q2-4q2and v2 corresponding to 2=-q+q2-4q2.

As t,xt0solution converges to origin.

Also, C1andC2 are arbitrary constants.

Dominant terms is C2e2tv2as 2is larger in magnitude, therefore distant trajectories are parallel to E2.

All trajectories converge to origin.Along the trajectory 1, the movement of the door slow down continuously until it reaches to the closed state as along this trajectory w decreases continuously.

Door slams if the trajectory 2 is followed that is initially if :

00<2=-qq2+4q2

From figure it observe that for condition <0door reaches<0 .

Hence, all trajectories converge to origin and it observe that for condition <0door reaches<0 .

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