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Use theorem 9.3.13 to solve the initial value problem

dx→dt=(1201)x→withx→(0)=[1-1] .

Hint: Find first x2(t) and then x1(t).

Short Answer

Expert verified

The solution iset1-2t-1

Step by step solution

01

Definition of first order linear differential equation.

Consider the differential equation f'(t)-af(t)=g(t)where g(t)is a smooth function and 'a'is a constant. Then the general solution will bef(t)=eat∫e-atg(t)dt.

02

Determination of the solution.

Consider the differential equation as follows.

dx→dt=1201x→A=1201A=1f't-1ft=0

Now, the differential equation is in the form as follows.

f't-aft=gt, where g(t) is a smooth function, then the general solution will be as follows.

ft=eat∫e-atgtdt

03

Compute the calculation of the solution.

Substitute the value 0 for g(t) and 1 for a inft=eat∫e-atgtdtas follows.

ft=eat∫e-atgtdtft=et∫e-t×0×dtft=et∫0×dtft=et.C

Here C is constant

Also it can be written as follows.

C=1-2t-1

The solution iset1-2t-1

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Most popular questions from this chapter

Consider an n×n matrix A with m distinct eigenvalues λ1,λ2,…,λm.

(a) Show that the initial value problemdx→dt=Ax→ withrole="math" localid="1660807946554" x→(0)=x→0 has a unique solutionrole="math" localid="1660807989045" x→(t)

(b) Show that the zero state is a stable equilibrium solution of the systemdx→dt=Ax→ if and only if the real part of all theλi is negative.Hint: Exercise 47 and Exercise 8.1.45 are helpful.

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