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Consider a noninvertible 2×2matrix A with a positive trace. What does the phase portrait of the systemdx→/dy=Ax→look like?

Short Answer

Expert verified

The phase portrait of the systemdx→/dy=Ax→ look like asymptotically stable

Step by step solution

01

Step 1:Explanation for the phase of the system dx→/dy=Ax→

Consider a noninvertible 2×2matrix A with a positive trace.

Where A is a real2×2matrix.

Then the zero state is an asymptotically stable equilibrium solution if and only if trA<0and detA>0

02

Explanation for the phase of the system dx→/dy=Ax→

Here is the phase looks like asymptotically stable.

λ1,2=p±iq

p2+q2=1λ1,2=±iq

The phase portrait of the system dx→/dy=Ax→look like asymptotically stable.

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