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Use eigenvalues to determine the stability of a dynamical system. Analyse the dynamical system, x→(t+1)=Ax→(t)where A is a real2×2matrix with eigenvaluesforthe matrices A in Exercises 1 through 10, determine whether the zero state is a stable equilibrium of the dynamicalsystem.x→(t+1)=Ax→(t)

A=[0.80-0.600.700.600.8]

Short Answer

Expert verified

The stability of the dynamical system using eigenvalues is unstable.

Step by step solution

01

solve the given matrix by eigenvalues:

EigenvaluesλofA are roots of the characteristic equation. Associated eigenvectors of A are nonzero solutions of the equation.(A−λI)x=0

Using characteristic equation,

det(A−λI)=0|0.8−λ00.600.7−λ00.600.8−λ|=0(0.8−λ)2(0.7−λ)−0.36(0.7−λ)=0(0.7−λ)(λ2−1.6λ+0.28)=0λ1=0.7,λ2=1.6±2.56−1.122=0.8±0.6i

Since,|λ2|=|λ3|=1then the equilibrium is unstable.

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