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For which values of constants a,b,c are the matrix diagonalizable?

[1ab01c001]

Short Answer

Expert verified

The matrix A is diagonalizable for the values of a = b = c = 0

Step by step solution

01

Calculating the value of of the matrix .

Consider an n×nmatrix A and a scalar λ. Then λis the eigenvalue of A if det(A-λ±ô)=0. This is called Characteristic equation of matrix .

The given matrix is 1ab01c001

This matrix has an upper triangular shape. As a result, the entries on its main diagonal are its eigenvalues.

They areλ1=1,λ2=1,λ3=1

Therefore , we need to calculate for λ=1,

(A-l)x=00ab00c000x1x2x3=000

02

Analyzing whether the matrix is diagonalizable.

For c≠0, we get x3=0. So, E1will be at most two-dimensional. For c=0,a≠0≠b,we will getax2+bx3=0

E1=100b0-aWhich is also a two-dimensional. So the matrix is diagonalizable only if

Finally we can conclude that A is diagonalizable for all a = b = c = 0

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