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91Ó°ÊÓ

Show that if matrix A is similar to B, A-λ±ôn thenis similar toB-λ±ôn, for all scalarsλ.

Short Answer

Expert verified

The matrix is clearly implying B-λ±ônis similar toA-λ±ôn

Step by step solution

01

Solving the matrix

Since A is similar to B, by definition, there exists a non-singular matrix

B=P-1AP

Therefore,

B-λ±ôn=P-1AP-λ±ôn=P-1AP-λ±Ê-1Pln

02

Substitute I and P

HereP-1P=l and Pl=lP=P

=P-1AP-λ±Ê-1lnP=P-1AP-P-1λ±ônPB-λ±ôn=P-1A-λ±ônP

Here, the final result is clearly implying B-λ±ônis similar toA-λ±ôn

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