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(a). If 2i is an eigenvalue of a real 2 × 2 matrix A, findA2.

(b). Give an example of a real 2 × 2 matrix A such that all the entries of A are nonzero and 2i is an eigenvalue of A. ComputeA2and check that your answer agrees with part (a).

Short Answer

Expert verified

(a). The solution for A2= -4I.

(b). The solution for A2= -4I . Thus, it agrees with part (a) answer.

Step by step solution

01

Define eigenvalue:

Eigenvalues are a set of specialized scales associated with a system of linear equations. The corresponding eigenvalue, often denoted byλ.

02

Find A2:

Given the eigenvalue of A is 2i, then the other eigenvalue is -2i.

So the equation is ,

fA(λ)=(λ−2i)(λ+2i)

=λ2+4

From this we get,

A2+4I=0

Calculating for A2,

role="math" localid="1664255493746" A2=-4I

03

Find and compare if it agrees with part (a):

So we get,

fA(λ)=(1−λ)(−1−λ)+5

=λ2+4

So in part (a),

λ=2iis an eigenvalue of A.

A2=−400−4

A2=-4I, so this agrees with part (a).

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