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Consider a diagonal n×nmatrix Awith rank A=r<n. Find the algebraic and the geometric multiplicity of the eigenvalue 0of Ain terms of rand n

Short Answer

Expert verified

the algebraic and the geometric multiplicity of the eigenvalue is

almu(0) = n - r, gemu (0) = n - r

Step by step solution

01

Geometric multiplicity

Consider an eigenvalue λof an n×nmatrix A. The dimension of eigenspace Eλ=ker(A-λ±ôn)is called the geometric multiplicity of eigenvalue λ, denoted gemu(λ). Thus,

gemu(λ)=nullity(A-ln)=n-rank(A-ln)

gemu(l)=dim(E1)=1

02

Solution of the problem

Since rank A=r<n , we can assume that the first columns of form a basis for imA. Since the other n - r columns are linear combinations of the first r columns, this means that almu.

Lastly, we get gemu(0) = dimker(A - 0l)=dimker A = n-dimimA = n -r

Here, the result is

almu(0) = n - r, gemu(0) = n - r

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