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For a given eigenvalue, find a basis of the associated eigenspace. Use the geometric multiplicities of the eigenvalues to determine whether a matrix is diagonalizable. For each of the matrices A in Exercises 1 through 20, find all (real) eigenvalues. Then find a basis of each eigenspace, and diagonalize A, if you can. Do not use technology

16(1100-1-1220)

Short Answer

Expert verified

The given matrix of A is not diagonalizable.

Step by step solution

01

Algebraic Versus.

Algebraic versus geometric multiplicity If 位 is an eigenvalues of a square matrix A,

then gemu(1)<almu(1)

detA-I=01-100-1--122-=0-(1-)(-1-)-2+2(1+)=0-(2+1)=01=0,2=-i,3=i

02

Find the eigenvalues.

Here, the only real eigenvalues is =0

Ax=01100-1-1220x1x2x3=000x1+x2=0,x2+x3=0

The basic for eigenspace is1-11=v1

Therefore, there is only one real eigenvalues, A is not a diagonalizable in 3.

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