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Consider the matrices A For which real numbers k is the zero state a stable equilibrium of the dynamical systemx→(t+1)=Ax→(t)

A=[0.1k0.30.3]

Short Answer

Expert verified

The Value of the matrix =−9730<k<2110

Step by step solution

01

Define Matrix

A matrix is a rectangular array of numbers or symbols which are generally arranged in rows and columns.

02

Calculation of the Value A

det(A−λI)=0|0.1−λk0.30.3−λ|=0(0.1−λ)(0.3−λ)−0.3k=0λ2−0.4λ+(0.03−0.3k)=0λ1,2=0.4±0.16−4(0.03−0.3k)2=0.2±0.04+1.2k2

03

Solving the Equationk≥-130

0.04+1.2k2<0.80.04+1.2k<1.60.04+1.2k<2.56k<2110

04

Solving the Equation In case on the other handk<-130

0.04+−0.04−1.2k4<10.12−1.2k<4k>−9730

The Equilibrium will be stable at−9730<k<2110

−9730<k<2110

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