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LetMn be therole="math" localid="1660405225698" nn matrix with l's on the main diagonal and directly above the main diagonal,role="math" localid="1660405220979" -1's directly below the main diagonal, androle="math" localid="1660405229621" 0's elsewhere. For example M4=[1100-11100-11100-11],

Let dn=det(Mn)

a. For n3, find a formula expressing dn in terms ofdn-1 anddn-2.
b. Find d1,d2,d3,d4, and d10.
c. For which positive integersn is the matrixMn invertible?

Short Answer

Expert verified

Therefore,

a) dn=dn-1+dn-2.

b) d1=1,d2=2,d3=3,d4=5,d10=89

c) Mnis invertible for all n.

Step by step solution

01

Step by Step Solution: Step 1: Matrix Definition

Matrix is aset of numbers arranged in rowsand columns so as to form a rectangular array.

The numbers are called the elements, or entries, of the matrix.

If there are mrows and ncolumns, the matrix is said to be a 鈥 mby n鈥 matrix, written 鈥 mn.鈥

02

(a)Step 2: To find the formula expressing in dn terms

Using the Laplace expansion along the first column, we have:

dn=1dn-1-(-1)1dn-2dn=dn-1+dn-2.

03

(b)Step 3: To find d1,d2,d3,d4 and d10.

It applies that:

dn=dn-1+dn-2.d1=1,d2=2,d3=3,d4=5,d10=89.

04

(c)Step 4: To find which positive integers matrix Mn of is invertible

Given the formula for recursion dn=dn-1+dn-2, Mnis invertible for all n .

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