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There exists a real number such that the matrix

[123456k789870065]Is invertible. .

Short Answer

Expert verified

Therefore,

K=3252 and it is invertible

So, the given statement is true.

Step by step solution

01

Matrix Definition

Matrix is aset of numbers arranged in rows and columns so as to form a rectangulararray.

The numbers are called the elements, or entries, of the matrix.

If there are m rows and n columns, the matrix is said to be a 鈥 m by n鈥 'matrix, written 鈥 mn鈥.

02

Given

Given matrix,

A=123456k789870065


03

To check whether the given condition is true or false 

We compute

detA=-6.124567897+5.12356k898

A=-69+5(7k-41)A=35k-259

So, for example, A is invertible for k=3252.

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Most popular questions from this chapter

Vandermonde determinants (introduced by Alexandre-Th茅ophile Vandermonde). Consider distinct real numbers a0,a1,.....,an.. We define(n+1)(n+1) the matrix

A=[11....1a0a1....ana02a12....a12a0na1n....ann]

Vandermonde showed that

det(A)=i>j(ai-aj)

the product of all differences(ai-aj), where exceeds j.
a. Verify this formula in the case ofn=1.
b. Suppose the Vandermonde formula holds forn=1. You are asked to demonstrate it for n. Consider the function

f(t)=det[11...11a0a1...an-1ta02a12...an-1t2...a0na1n...an-1ntn]

Explain why f(t) is a polynomial of nthdegree. Find the coefficient k oftn using Vandermonde's formula fora0,...,an-1. Explain why

role="math" localid="1659522435181" f(a0)=f(a1)=...=f(an-1)=0

Conclude that

f(t)=k(t-a0)(t-a1)...(t-an-1)

for the scalar k you found above. Substitutet=an to demonstrate Vandermonde's formula.

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