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Find the determinant of the\((2n) \times (2n)\)matrix

\(A = \left( {\begin{array}{*{20}{c}}0&{{I_n}}\\{{I_n}}&0\end{array}} \right).\)

Short Answer

Expert verified

Therefore, the determinant of the given matrix is given by,\(\det A = {( - 1)^n}\).

Step by step solution

01

Definition

A determinant is a unique number associated with a square matrix.

A determinant is a scalar value that is a function of the entries of a square matrix.

It is the signed factor by which areas are scaled by this matrix. If the sign is negative the matrix reverses orientation.

02

Given

Given matrix,

\(A = \left( {\begin{array}{*{20}{c}}0&{{I_n}}\\{{I_n}}&0\end{array}} \right).\)

03

To find the determinant

To obtain the identity matrix\({I_{2n}}\), we first switch the first and \((n + 1)\)-th row, then we switch the second and\((n + 2)\)-th row, etc.

Lastly, we switch the\(n\) -th and\(2n\) -th row.

We had \(n\) row interchanges, so\(\det A = {( - 1)^n}\).

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