/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 For two invertible \(n \times n\... [FREE SOLUTION] | 91Ó°ÊÓ

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For two invertible \(n \times n\) matrices \(A\) and \(B,\) determine which of the formulas stated are necessarily true. $$A B B^{-1} A^{-1}=I_{n}$$

Short Answer

Expert verified
\(AB B^{-1} A^{-1} = I_{n}\) is a true statement as it simplifies to the identity matrix, utilizing the properties of matrix multiplication and inversion.

Step by step solution

01

Understand Matrix Multiplication

Recall that matrix multiplication is associative. This means that when we multiply several matrices together, we can choose how to group the matrices without changing the result. For instance, \( (AB)(CD) = A(BC)D = ABCD \).
02

Apply the Definition of Inverse Matrices

Understand that for an invertible matrix \(M\), its inverse \(M^{-1}\) is defined such that \(MM^{-1} = M^{-1}M = I_n\), where \(I_n\) is the identity matrix of the same size. The product of a matrix and its inverse results in the identity matrix.
03

Evaluate the Given Formula

Evaluate the given formula using the properties of matrix multiplication and inverses. \((AB)(B^{-1}A^{-1}) = A(BB^{-1})A^{-1} = AI_nA^{-1} = AA^{-1} = I_n\). Thus, the formula \(AB B^{-1} A^{-1} = I_{n}\) is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Multiplication
Matrix multiplication is a fundamental operation in linear algebra that combines two matrices to produce a third matrix. For matrices to be multiplicable, the number of columns in the first matrix must match the number of rows in the second matrix. The resulting matrix has dimensions determined by the rows of the first matrix and the columns of the second matrix.

Consider two matrices, Matrix A of size ). When these are multiplied, the resulting matrix C will have the size of A's rows by B's columns. The entry in the ith row and jth column of Matrix C is computed as a sum product of the elements from the ith row of A and the jth column of B.
  • In mathematical notation, if C = AB, then ). Understanding this process is crucial for comprehending more complex operations involving matrices, such as finding inverses or determining matrix equities.
Associative Property
The associative property is a rule that indicates how we group numbers when adding or multiplying does not change the result. This property is key to simplifying expressions and solving equations involving matrices. When we multiply three or more matrices, we can group them in different ways without affecting the final product.

For example, if we have three matrices A, B, and C, the associative property assures us that ). This property does not apply to matrix subtraction or division, as these operations are not associative. Understanding the associative property is essential when working with multiple matrix products, as it allows us to determine the most convenient order of multiplication, potentially simplifying the computation.
Inverse Matrices
An inverse matrix is similar to the reciprocal of a number in arithmetic. For a square matrix A, the inverse is denoted by ). This special matrix, when multiplied with the original matrix, yields the identity matrix of the same dimension, symbolizing the number one in matrix terms.

A matrix must be square, meaning it has an equal number of rows and columns, and invertible—having a determinant that is not zero. Only then can we find an inverse for it. The equation ) is a quantitative expression of this concept. Finding the inverse of a matrix is crucial in solving systems of linear equations, as it provides a way to divide by matrices, although the term 'division' is not used in matrix algebra.
Identity Matrix
The identity matrix, commonly denoted as ), is the equivalent of the number 1 in matrix math. It is a square matrix with ones on the diagonal from the upper left to the lower right and zeros everywhere else. The key characteristic of the identity matrix is that it does not change any matrix it is multiplied with, hence the name identity.

For any square matrix A of the same size, the equations ) hold true. This property makes the identity matrix a pivotal element in matrix operations, serving as a neutral element in matrix multiplication. Understanding and recognizing the identity matrix is vital for verifying matrix equations and solving linear systems.

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Most popular questions from this chapter

In this exercise we will verify part (b) of Theorem 2.3 .11 in the special case when \(A\) is the transition matrix \(\left[\begin{array}{ll}0.4 & 0.3 \\\ 0.6 & 0.7\end{array}\right]\) and \(\vec{x}\) is the distribution vector \(\left[\begin{array}{l}1 \\ 0\end{array}\right]\) [We will not be using parts (a) and (c) of Theorem \(2.3 .11 .\) ] The general proof of Theorem 2.3 .11 runs along similar lines, as we will see in Chapter 7. a. Compute \(A\left[\begin{array}{l}1 \\ 2\end{array}\right]\) and \(A\left[\begin{array}{c}1 \\ -1\end{array}\right] .\) Write \(A\left[\begin{array}{c}1 \\ -1\end{array}\right]\) as a scalar multiple of the vector \(\left[\begin{array}{c}1 \\ -1\end{array}\right]\). b. Write the distribution vector \(\vec{x}=\left[\begin{array}{l}1 \\\ 0\end{array}\right]\) as a linear combination of the vectors \(\left[\begin{array}{l}1 \\ 2\end{array}\right]\) and \(\left[\begin{array}{c}1 \\\ -1\end{array}\right]\). c. Use your answers in parts (a) and (b) to write \(A \vec{x}\) as a linear combination of the vectors \(\left[\begin{array}{l}1 \\ 2\end{array}\right]\) and \(\left[\begin{array}{c}1 \\ -1\end{array}\right]\) More generally, write \(A^{m} \vec{x}\) as a linear combination of the vectors \(\left[\begin{array}{l}1 \\ 2\end{array}\right]\) and \(\left[\begin{array}{c}1 \\\ -1\end{array}\right],\) for any positive integer \(m\). See Exercise 81.

Is the product of two lower triangular matrices a lower triangular matrix as well? Explain your answer.Consider the matrix \\[A=\left[\begin{array}{lll} 1 & 2 & 3 \\ 2 & 6 & 7 \\ 2 & 2 & 4 \end{array}\right].\\] a. Find lower triangular elementary matrices \(E_{1}\) \(E_{2}, \ldots, E_{m}\), such that the product $$E_{m} \cdots E_{2} E_{1} A$$ is an upper triangular matrix \(U\). Hint: Use elementary row operations to eliminate the entries below the diagonal of \(A\). b. Find lower triangular elementary matrices \(M_{1}\) \(M_{2}, \ldots, M_{m}\) and an upper triangular matrix \(U\) such that \\[A=M_{1} M_{2} \cdots M_{m} U.\\] c. Find a lower triangular matrix \(L\) and an upper triangular matrix \(U\) such that \\[A=L U.\\] Such a representation of an invertible matrix is called an \(L U\) -factorization. The method outlined in this exercise to find an \(L U\) -factorization can be streamlined somewhat, but we have seen the major ideas. An \(L U\) -factorization (as introduced here) does not always exist. See Exercise 92 d. Find a lower triangular matrix \(L\) with 1 's on the diagonal, an upper triangular matrix \(U\) with 1 's on the diagonal, and a diagonal matrix \(D\) such that \(A=L D U .\) Such a representation of an invertible matrix is called an \(L D U\) -factorization.

Find all upper triangular \(2 \times 2\) matrices \(X\) such that \(X^{2}\) is the zero matrix.

Decide whether the linear transformations are invertible. Find the inverse transformation if it exists. Do the computations with paper and pencil. Show all your work. $$\begin{array}{l} y_{1}=x_{1}+2 x_{2} \\ y_{2}=4 x_{1}+8 x_{2} \end{array}$$

Consider the matrices of the form \(A=\left[\begin{array}{rr}a & b \\ b & -a\end{array}\right],\) where \(a\) and \(b\) are arbitrary constants. For which values of \(a\) and \(b\) is \(A^{-1}=A ?\)

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