/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Consider the matrix $$D_{\alpha}... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider the matrix $$D_{\alpha}=\left[\begin{array}{cr}\cos \alpha & -\sin \alpha \\\\\sin \alpha & \cos \alpha\end{array}\right]$$ We know that the linear transformation \(T(\vec{x})=D_{\alpha} \vec{x}\) is a counterclockwise rotation through an angle \(\alpha\). a. For two angles, \(\alpha\) and \(\beta,\) consider the products \(D_{\alpha} D_{\beta}\) and \(D_{\beta} D_{\alpha} .\) Arguing geometrically, describe the linear transformations \(\vec{y}=D_{\alpha} D_{\beta} \vec{x}\) and \(\vec{y}=\) \(D_{\beta} D_{\alpha} \vec{x} .\) Are the two transformations the same? b. Now compute the products \(D_{\alpha} D_{\beta}\) and \(D_{\beta} D_{\alpha} .\) Do the results make sense in terms of your answer in part (a)? Recall the trigonometric identities $$\begin{array}{l} \sin (\alpha \pm \beta)=\sin \alpha \cos \beta \pm \cos \alpha \sin \beta \\ \cos (\alpha \pm \beta)=\cos \alpha \cos \beta \mp \sin \alpha \sin \beta \end{array}$$

Short Answer

Expert verified
Geometrically, both \(D_\alpha D_\beta \vec{x}\) and \(D_\beta D_\alpha \vec{x}\) represent a total counterclockwise rotation by \(\alpha + \beta\). After the matrix multiplication, the resulting products show that these transformations are the same, affirming that rotations in the plane are commutative.

Step by step solution

01

Geometric Interpretation of Transformations

Geometrically, the transformation \(D_\alpha D_\beta \vec{x}\) represents a counterclockwise rotation of angle \(\alpha\) followed by another counterclockwise rotation of angle \(\beta\). Similarly, the transformation \(D_\beta D_\alpha \vec{x}\) represents a counterclockwise rotation of angle \(\beta\) followed by \(\alpha\). Both transformations result in a net rotation by \(\alpha + \beta\). As rotations are commutative in the plane, these transformations should be equivalent.
02

Matrix Product for \(D_\alpha D_\beta\)

Compute the product of the two matrices \(D_\alpha\) and \(D_\beta\) by multiplying them as follows: \[D_\alpha D_\beta = \left[\begin{array}{cc}\cos \alpha & -\sin \alpha \sin \alpha & \cos \alpha\end{array}\right]\left[\begin{array}{cc}\cos \beta & -\sin \beta \sin \beta & \cos \beta\end{array}\right]\] Apply standard matrix multiplication rules to obtain the resulting matrix which should represent a combined rotation by \(\alpha + \beta\).
03

Matrix Product for \(D_\beta D_\alpha\)

Likewise, compute the product of the matrices \(D_\beta\) and \(D_\alpha\) by reversing the order in the matrix multiplication process: \[D_\beta D_\alpha = \left[\begin{array}{cc}\cos \beta & -\sin \beta \sin \beta & \cos \beta\end{array}\right]\left[\begin{array}{cc}\cos \alpha & -\sin \alpha \sin \alpha & \cos \alpha\end{array}\right]\] Again, use standard matrix multiplication rules to find the result.
04

Comparing the Results

Compare the resulting matrices from both multiplication processes using the trigonometric identities. The final matrices should be equivalent and represent a rotation by \(\alpha + \beta\). The matrices should be the same since rotation is a commutative operation in two dimensions, hence, the transformation \(D_\alpha D_\beta \vec{x}\) is the same as the transformation \(D_\beta D_\alpha \vec{x}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Transformation
In the context of linear algebra, a linear transformation is a mapping between two vector spaces that preserves the operations of vector addition and scalar multiplication. The transformation is called 'linear' because it transforms a line into another line without bending or curving it, maintaining straightness and parallelism of lines. For instance, the matrix
\[D_{\alpha} = \begin{pmatrix}\cos \alpha & -\sin \alpha \sin \alpha & \cos \alpha\end{pmatrix}\]
is associated with a linear transformation that performs a counterclockwise rotation of a vector in the plane by an angle \(\alpha\). This matrix, when multiplied with a vector \(\vec{x}\), rotates \(\vec{x}\) while keeping the origin fixed, showcasing the essence of a linear transformation in preserving grid lines and origin.Rotations in the plane are particular examples of linear transformations, with special rules like preserving distances and angles, making them 'isometries'. Comprehending the matrix form of such transformations guides students not only in visualizing rotations but also in performing complex operations like consecutive rotations, leading into the concept of the commutative property.
Commutative Property of Rotations
The commutative property of rotations refers to the fact that the order of applying multiple rotations in the plane does not affect the final position of an object. In linear algebra terms, when you multiply two rotation matrices like \(D_{\alpha}\) and \(D_{\beta}\), regardless of the order in which you perform the multiplication, the resulting transformation is the same. This property is fundamental because it simplifies complex calculations and is not always true for all types of transformations.
For example, when you perform a rotation by \(\alpha\) followed by \(\beta\), or \(\beta\) followed by \(\alpha\), both sequences result in a rotation by \(\alpha + \beta\). This can be seen geometrically and verified by matrix multiplication. Understanding this concept is critical because it helps students realize that rotations can be combined in a flexible manner without worrying about order, which is particularly useful in applications such as computer graphics and robotics.
Trigonometric Identities
Trigonometric identities are mathematical equations that express one trigonometric function in terms of others. They are essential tools in both pure and applied mathematics, providing insights that assist in simplifying expressions and solving equations. The identities
\[\begin{align*}\sin(\alpha \pm \beta) & = \sin \alpha \cos \beta \pm \cos \alpha \sin \beta, \cos(\alpha \pm \beta) & = \cos \alpha \cos \beta \mp \sin \alpha \sin \beta\end{align*}\]
play a crucial role in the analysis of rotations in linear algebra. By using these identities, students can derive the components of a matrix representing a rotation by an angle \(\alpha + \beta\)—the angles being additive when the rotations are combined. This proves invaluable when demonstrating that the product of two rotation matrices, akin to consecutive rotations, results in another rotation matrix with angles that adhere to these identities. An understanding of these identities equips students with the ability to handle more complex rotational transformations and lays the groundwork for further studies in mathematics and physics.

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Most popular questions from this chapter

Consider the matrices of the form \(A=\left[\begin{array}{rr}a & b \\ b & -a\end{array}\right],\) where \(a\) and \(b\) are arbitrary constants. For which values of \(a\) and \(b\) is \(A^{-1}=A ?\)

For each of the mini-Webs in Exercises 50 through 52 a. find the transition matrix A as defined in Example 9 b. find the equilibrium distribution, and c. find the web page(s) with the highest (naive) PageRank. Feel free to use technology throughout.. $$\begin{array}{l} 1 \rightarrow 2 \\ \uparrow\downarrow \nearrow\\\ 3 \end{array}$$

In the financial pages of a newspaper, one can sometimes find a table (or matrix) listing the exchange rates between currencies. In this exercise we will consider a miniature version of such a table, involving only the Canadian dollar (C\$) and the South African Rand (ZAR). Consider the matrix \(\mathrm{CS} \quad \mathrm{ZAR}\) \\[ A=\left[\begin{array}{cc} 1 & 1 / 8 \\ 8 & 1 \end{array}\right] \begin{array}{c} \mathrm{CS} \\ \mathrm{ZAR} \end{array} \\] representing the fact that \(\mathrm{C} \$ 1\) is worth \(\mathrm{ZAR} 8\) (as of September 2012 ). a. After a trip you have \(\mathrm{C} \$ 100\) and \(\mathrm{ZAR} 1,600\) in your pocket. We represent these two values in the vector \(\vec{x}=\left[\begin{array}{c}100 \\ 1,600\end{array}\right] .\) Compute \(A \vec{x} .\) What is the practical significance of the two components of the vector \(A \vec{x} ?\) b. Verify that matrix \(A\) fails to be invertible. For which vectors \(\vec{b}\) is the system \(A \vec{x}=\vec{b}\) consistent? What is the practical significance of your answer? If the system \(A \vec{x}=\vec{b}\) is consistent, how many solutions \(\vec{x}\) are there? Again, what is the practical significance of the answer?

a. Find the scaling matrix \(A\) that transforms \(\left[\begin{array}{r}2 \\\ -1\end{array}\right]\) into \(\left[\begin{array}{r}8 \\ -4\end{array}\right]\) b. Find the orthogonal projection matrix \(B\) that transforms \(\left[\begin{array}{l}2 \\ 3\end{array}\right]\) into \(\left[\begin{array}{l}2 \\ 0\end{array}\right]\) c. Find the rotation matrix \(C\) that transforms \(\left[\begin{array}{l}0 \\\ 5\end{array}\right]\) into \(\left[\begin{array}{l}3 \\ 4\end{array}\right]\) d. Find the shear matrix \(D\) that transforms \(\left[\begin{array}{l}1 \\\ 3\end{array}\right]\) into \(\left[\begin{array}{l}7 \\ 3\end{array}\right]\) e. Find the reflection matrix \(E\) that transforms \(\left[\begin{array}{l}7 \\\ 1\end{array}\right]\) into \(\left[\begin{array}{r}-5 \\ 5\end{array}\right]\)

Which of the (nonlinear) transformations from \(\mathbb{R}^{2}\) to \(\mathbb{R}^{2}\) are invertible? Find the inverse if it exists. $$\left[\begin{array}{l} y_{1} \\ y_{2} \end{array}\right]=\left[\begin{array}{c} x_{1}+x_{2} \\ x_{1} \cdot x_{2} \end{array}\right]$$

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