Prove that any two of the following expressions are equal:
$$
\begin{aligned}
&\mathbf{v}+(\mathbf{w}+(\mathbf{x}+\mathbf{y})) \\
&\mathbf{v}+((\mathbf{w}+\mathbf{x})+\mathbf{y}) \\
The point is that even though addition of vectors always combines exactly two
vectors to produce a third, it doesn't really matter which pairs are added
together first. Consequently, it is customary to eliminate the parentheses
when dealing with sums of vectors. The vector represented by any one of the
five expressions above will be denoted
\(\mathbf{v}+\mathbf{w}+\mathbf{x}+\mathbf{y}\). To show why this sloppiness is
legitimate when an arbitrary number of vectors is to be summed would require
an elaborate system for keeping track of parentheses. If you are familiar with
proofs by induction, you may want to regard this as a challenge. In any case,
we want to be free from writing all these parentheses. From now on we will
rely on our happy experiences with real numbers where a similar problem is
ignored.
&(\mathbf{v}+\mathbf{w})+(\mathbf{x}+\mathbf{y}) \\
&(\mathbf{v}+(\mathbf{w}+\mathbf{x}))+\mathbf{y} \\
&((\mathbf{v}+\mathbf{w})+\mathbf{x})+\mathbf{v}
\end{aligned}
$$