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Show that if \(B\) is \(m \times n\), then \({B^T}B\) is positive semidefinite; and if \(B\) is \(n \times n\) and invertible, then \({B^T}B\) is positive definite.

Short Answer

Expert verified

It is proved that if \(B\) is \(m \times n\), then \({B^T}B\) is positive semidefinite; and if \(B\) is \(n \times n\) and invertible, then \({B^T}B\) is positive definite.

Step by step solution

01

Step 1: Find the characteristic polynomial

We need to prove that\({B^T}B\)is a symmetric matrix and the quadratic form\({{\bf{x}}^T}\left( {{B^T}B} \right){\bf{x}} \ge 0\)for all\({\bf{x}}\)that proves\({B^T}P\)positive semi-definite.

Now consider,

\(\begin{aligned}{}{\left( {{B^T}B} \right)^T} &= {B^T}{\left( {{B^T}} \right)^T}\\ &= {B^T}B\end{aligned}\)

Thus, the matrix \({B^T}B\) is a symmetric matrix.

02

Show that \({B^T}B\) is positive semi definite

Consider the quadratic form \({{\bf{x}}^T}\left( {{B^T}B} \right){\bf{x}}\).

\(\begin{aligned}{}{{\bf{x}}^T}\left( {{B^T}B} \right){\bf{x}} &= \left( {{{\bf{x}}^T}{B^T}} \right)B{\bf{x}}\\ &= {\left( {B{\bf{x}}} \right)^T}B{\bf{x}}\\ &= {\left\| {B{\bf{x}}} \right\|^2}\end{aligned}\)

Thus, \({{\bf{x}}^T}\left( {{B^T}B} \right){\bf{x}} \ge 0\).

Therefore, the matrix \({B^T}B\) is positive semi-definite.

03

Show that \({B^T}B\) is positive definite

Assume \({{\bf{x}}^T}\left( {{B^T}B} \right){\bf{x}} = 0\)then we have,

\(\begin{aligned}{}{{\bf{x}}^T}\left( {{B^T}B} \right){\bf{x}} &= 0\\\left( {{{\bf{x}}^T}{B^T}} \right)B{\bf{x}} &= 0\\{\left( {B{\bf{x}}} \right)^T}B{\bf{x}} &= 0\\{\left\| {B{\bf{x}}} \right\|^2} &= 0\end{aligned}\)

It is given that the matrix\(B\)is invertible, hence the equation\(B{\bf{x}} = 0\)has a trivial solution only. Therefore, we have,\({{\bf{x}}^T}\left( {{B^T}B} \right){\bf{x}} = 0\)then\({\bf{x}} = 0\)and\({\bf{x}} \ne 0\),\({{\bf{x}}^T}\left( {{B^T}B} \right){\bf{x}} > 0\).

Thus,\({B^T}B\)is a positive definite.

It is proved that if \(B\) is \(m \times n\), then \({B^T}B\)is positive semidefinite; and if\(B\) is \(n \times n\) and invertible, then \({B^T}B\)is positive definite.

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Most popular questions from this chapter

Orthogonally diagonalize the matrices in Exercises 13鈥22, giving an orthogonal matrix \(P\) and a diagonal matrix \(D\). To save you time, the eigenvalues in Exercises 17鈥22 are: (17) \( - {\bf{4}}\), 4, 7; (18) \( - {\bf{3}}\), \( - {\bf{6}}\), 9; (19) \( - {\bf{2}}\), 7; (20) \( - {\bf{3}}\), 15; (21) 1, 5, 9; (22) 3, 5.

16. \(\left( {\begin{aligned}{{}}{\,6}&{ - 2}\\{ - 2}&{\,\,\,9}\end{aligned}} \right)\)

In Exercises 17鈥24, \(A\) is an \(m \times n\) matrix with a singular value decomposition \(A = U\Sigma {V^T}\) , where \(U\) is an \(m \times m\) orthogonal matrix, \({\bf{\Sigma }}\) is an \(m \times n\) 鈥渄iagonal鈥 matrix with \(r\) positive entries and no negative entries, and \(V\) is an \(n \times n\) orthogonal matrix. Justify each answer.

17. Show that if \(A\) is square, then \(\left| {{\bf{det}}A} \right|\) is the product of the singular values of \(A\).

Question: Mark Each statement True or False. Justify each answer. In each part, A represents an \(n \times n\) matrix.

  1. If A is orthogonally diagonizable, then A is symmetric.
  2. If A is an orthogonal matrix, then A is symmetric.
  3. If A is an orthogonal matrix, then \(\left\| {A{\bf{x}}} \right\| = \left\| {\bf{x}} \right\|\) for all x in \({\mathbb{R}^n}\).
  4. The principal axes of a quadratic from \({{\bf{x}}^T}A{\bf{x}}\) can be the columns of any matrix P that diagonalizes A.
  5. If P is an \(n \times n\) matrix with orthogonal columns, then \({P^T} = {P^{ - {\bf{1}}}}\).
  6. If every coefficient in a quadratic form is positive, then the quadratic form is positive definite.
  7. If \({{\bf{x}}^T}A{\bf{x}} > {\bf{0}}\) for some x, then the quadratic form \({{\bf{x}}^T}A{\bf{x}}\) is positive definite.
  8. By a suitable change of variable, any quadratic form can be changed into one with no cross-product term.
  9. The largest value of a quadratic form \({{\bf{x}}^T}A{\bf{x}}\), for \(\left\| {\bf{x}} \right\| = {\bf{1}}\) is the largest entery on the diagonal A.
  10. The maximum value of a positive definite quadratic form \({{\bf{x}}^T}A{\bf{x}}\) is the greatest eigenvalue of A.
  11. A positive definite quadratic form can be changed into a negative definite form by a suitable change of variable \({\bf{x}} = P{\bf{u}}\), for some orthogonal matrix P.
  12. An indefinite quadratic form is one whose eigenvalues are not definite.
  13. If P is an \(n \times n\) orthogonal matrix, then the change of variable \({\bf{x}} = P{\bf{u}}\) transforms \({{\bf{x}}^T}A{\bf{x}}\) into a quadratic form whose matrix is \({P^{ - {\bf{1}}}}AP\).
  14. If U is \(m \times n\) with orthogonal columns, then \(U{U^T}{\bf{x}}\) is the orthogonal projection of x onto ColU.
  15. If B is \(m \times n\) and x is a unit vector in \({\mathbb{R}^n}\), then \(\left\| {B{\bf{x}}} \right\| \le {\sigma _{\bf{1}}}\), where \({\sigma _{\bf{1}}}\) is the first singular value of B.
  16. A singular value decomposition of an \(m \times n\) matrix B can be written as \(B = P\Sigma Q\), where P is an \(m \times n\) orthogonal matrix and \(\Sigma \) is an \(m \times n\) diagonal matrix.
  17. If A is \(n \times n\), then A and \({A^T}A\) have the same singular values.

Question: 12. Exercises 12鈥14 concern an \(m \times n\) matrix \(A\) with a reduced singular value decomposition, \(A = {U_r}D{V_r}^T\), and the pseudoinverse \({A^ + } = {U_r}{D^{ - 1}}{V_r}^T\).

Verify the properties of\({A^ + }\):

a. For each\({\rm{y}}\)in\({\mathbb{R}^m}\),\(A{A^ + }{\rm{y}}\)is the orthogonal projection of\({\rm{y}}\)onto\({\rm{Col}}\,A\).

b. For each\({\rm{x}}\)in\({\mathbb{R}^n}\),\({A^ + }A{\rm{x}}\)is the orthogonal projection of\({\rm{x}}\)onto\({\rm{Row}}\,A\).

c. \(A{A^ + }A = A\)and \({A^ + }A{A^ + } = {A^ + }\).

Suppose A is invertible and orthogonally diagonalizable. Explain why \({A^{ - {\bf{1}}}}\) is also orthogonally diagonalizable.

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