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Let \(D = \left( {\begin{aligned}{*{20}{c}}{.{\bf{005}}}&{.{\bf{002}}}&{.{\bf{001}}}\\{.{\bf{002}}}&{.{\bf{004}}}&{.{\bf{002}}}\\{.{\bf{001}}}&{.{\bf{002}}}&{.{\bf{005}}}\end{aligned}} \right)\) be a flexibility matrix, with flexibility measured in inches per pound. Suppose that forces of 30, 50, and 20 lb are applied at points 1, 2, and, 3, respectively, in figure 1 of Example 3. Find the corresponding deflections.

Short Answer

Expert verified

0.27 in, 0.30 in, and 0.23 in

Step by step solution

01

Find the force matrix

The force matrix is \(f = \left( {\begin{aligned}{*{20}{c}}{30}\\{50}\\{20}\end{aligned}} \right)\).

02

Find the corresponding deflection

Solve the equation \(y = Df\) to find the corresponding deflection.

\(\begin{aligned}{c}y = \left( {\begin{aligned}{*{20}{c}}{.005}&{.002}&{.001}\\{.002}&{.004}&{.002}\\{.001}&{.002}&{.005}\end{aligned}} \right)\left( {\begin{aligned}{*{20}{c}}{30}\\{50}\\{20}\end{aligned}} \right)\\ = \left( {\begin{aligned}{*{20}{c}}{0.15 + 0.1 + 0.02}\\{0.06 + 0.2 + 0.04}\\{0.03 + 0.1 + 0.1}\end{aligned}} \right)\\ = \left( {\begin{aligned}{*{20}{c}}{0.27}\\{0.30}\\{0.23}\end{aligned}} \right)\end{aligned}\)

So, the deflections are 0.27 in, 0.30 in, and 0.23 in at points 1, 2, and 3, respectively.

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Suppose block matrix \(A\) on the left side of (7) is invertible and \({A_{{\bf{11}}}}\) is invertible. Show that the Schur component \(S\) of \({A_{{\bf{11}}}}\) is invertible. [Hint: The outside factors on the right side of (7) are always invertible. Verify this.] When \(A\) and \({A_{{\bf{11}}}}\) are invertible, (7) leads to a formula for \({A^{ - {\bf{1}}}}\), using \({S^{ - {\bf{1}}}}\) \(A_{{\bf{11}}}^{ - {\bf{1}}}\), and the other entries in \(A\).

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\(A = \left( {\begin{aligned}{*{20}{c}}2&0&{ - 1}\\4&{ - 5}&2\end{aligned}} \right)\), \(B = \left( {\begin{aligned}{*{20}{c}}7&{ - 5}&1\\1&{ - 4}&{ - 3}\end{aligned}} \right)\), \(C = \left( {\begin{aligned}{*{20}{c}}1&2\\{ - 2}&1\end{aligned}} \right)\), \(D = \left( {\begin{aligned}{*{20}{c}}3&5\\{ - 1}&4\end{aligned}} \right)\) and \(E = \left( {\begin{aligned}{*{20}{c}}{ - 5}\\3\end{aligned}} \right)\)

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