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Explain why the columns of an \(n \times n\) matrix Aare linearly independent when Ais invertible.

Short Answer

Expert verified

The columns of the\(n \times n\)matrix Aare linearly independent when Ais invertible because the matrixhas n pivots.

Step by step solution

01

Write the algorithm for obtaining \({A^{ - 1}}\)

The inverse of the\(m \times m\)matrix A can be computed using the augmented matrix\(\left( {\begin{aligned}{*{20}{c}}A&I\end{aligned}} \right)\), where\(I\)is theidentity matrix. Matrix Ahas an inverse only if \(\left( {\begin{aligned}{*{20}{c}}A&I\end{aligned}} \right)\) is row equivalent to \(\left( {\begin{aligned}{*{20}{c}}I&{{A^{ - 1}}}\end{aligned}} \right)\).

02

Explain the invertible and linear independence of the matrix

Recall that identity matrix A has n pivot columns (or pivots).

From the above algorithm of the inverse of matrix A, matrix A and identity matrix I are row equivalent. So, matrix Ahas n pivots.

Also, by definition, if the matrix has n pivots, then matrix A islinearly independent.

If the matrix equation\(A{\bf{x}} = 0\)is considered, then it has one solution. It means the columns of the\(n \times n\)matrix Aare linearly independent when Aisinvertible.

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Most popular questions from this chapter

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