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In Exercises 7-12, describe all solutions of in parametric vector form, where is row equivalent to the given matrix.

9.

Short Answer

Expert verified

The general solution in the parametric vector form is \[x = {x_2}\left[ {\begin{array}{*{20}{c}}3\\1\\0\end{array}} \right] + {x_3}\left[ {\begin{array}{*{20}{c}}{ - 2}\\0\\1\end{array}} \right]\].

Step by step solution

01

Write the matrix as an augmented matrix

The augmented matrix \(\left[ {\begin{array}{*{20}{c}}A&0\end{array}} \right]\) for the given matrix is represented as:

\(\left[ {\begin{array}{*{20}{c}}3&{ - 9}&6&0\\{ - 1}&3&{ - 2}&0\end{array}} \right]\)

02

Apply row operation

Perform an elementaryrow operation to produce the first augmented matrix.

Multiply row 1 by \(\frac{1}{3}\).

\[\left[ {\begin{array}{*{20}{c}}1&{ - 3}&2&0\\{ - 1}&3&{ - 2}&0\end{array}} \right]\]

03

Apply row operation

Perform an elementary row operation to produce the second augmented matrix.

Perform the sum of \(1\) times row 1 and row 2 at row 2.

\[\left[ {\begin{array}{*{20}{c}}1&{ - 3}&2&0\\0&0&0&0\end{array}} \right]\]

04

Convert the matrix into the equation

To obtain the solution of the system of equations, you have to convert the augmented matrix into the system of equations again.

Write the obtained matrix \[\left[ {\begin{array}{*{20}{c}}1&{ - 3}&2&0\\0&0&0&0\end{array}} \right]\]into the equation notation.

\[\begin{array}{c}{x_1} - 3{x_2} + 2{x_3} = 0\\0 = 0\end{array}\]\(Ax = 0\)

05

Determine the basic variable and free variable of the system

The variables corresponding to pivot columns in the matrix are called basic variables.The other variable is called a free variable.

\({x_1}\)is a basic variable, and \({x_2}\) and \({x_3}\) are free variables.

Thus, \({x_1} = 3{x_2} - 2{x_3}\).

06

Determine the general solution in the parametric vector form

Sometimes the parametric form of an equation is written as\(x = s{\mathop{\rm u}\nolimits} + t{\mathop{\rm v}\nolimits} \,\,\,\left( {s,t\,{\mathop{\rm in}\nolimits} \,\mathbb{R}} \right)\).

The general solution of \(Ax = 0\) in the parametric vector form can be represented as:

\(\begin{array}{c}x = \left( {\begin{array}{*{20}{c}}{{x_1}}\\{{x_2}}\\{{x_3}}\end{array}} \right)\\ = \left( {\begin{array}{*{20}{c}}{3{x_2} - 2{x_3}}\\{{x_2}}\\{{x_3}}\end{array}} \right)\\ = \left( {\begin{array}{*{20}{c}}{3{x_2}}\\{{x_2}}\\0\end{array}} \right) + \left( {\begin{array}{*{20}{c}}{ - 2{x_3}}\\0\\{{x_3}}\end{array}} \right)\\ = {x_2}\left( {\begin{array}{*{20}{c}}3\\1\\0\end{array}} \right) + {x_3}\left( {\begin{array}{*{20}{c}}{ - 2}\\0\\1\end{array}} \right)\end{array}\)

Thus, the general solution in the parametric vector form is \(x = {x_2}\left( {\begin{array}{*{20}{c}}3\\1\\0\end{array}} \right) + {x_3}\left( {\begin{array}{*{20}{c}}{ - 2}\\0\\1\end{array}} \right)\).

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Most popular questions from this chapter

Determine the values(s) of \(h\) such that matrix is the augmented matrix of a consistent linear system.

18. \(\left[ {\begin{array}{*{20}{c}}1&{ - 3}&{ - 2}\\5&h&{ - 7}\end{array}} \right]\)

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The solutions \(\left( {x,y,z} \right)\) of a single linear equation \(ax + by + cz = d\)

form a plane in \({\mathbb{R}^3}\) when a, b, and c are not all zero. Construct sets of three linear equations whose graphs (a) intersect in a single line, (b) intersect in a single point, and (c) have no points in common. Typical graphs are illustrated in the figure.

Three planes intersecting in a line.

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Three planes intersecting in a point.

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(³¦â€™)

In Exercises 3 and 4, display the following vectors using arrows

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4. u and v as in Exercise 2

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