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91Ó°ÊÓ

Find the polynomial of degree 2[a polynomial of the form f(t)=a+bt+ct2] whose graph goes through the points localid="1659342678677" (1,-1),(2,3)and(3,13).Sketch the graph of the polynomial.

Short Answer

Expert verified

The polynomial of degree 2 whose graph goes through the points(1,-1),(2,3)and(3,13)isf(t)=1-5t+3t2.The graph is,

Step by step solution

01

Consider the points and substitute these in the standard equation

A polynomial of degree 2 is of the formf(t)=a+bt+ct2. Consider a polynomial of degree 2 and substitute given point in them as:

role="math" localid="1659342005093" f1t=a+bt1+c12-1=a+b1+a(1)2

role="math" localid="1659342115449" f2t=a+bt2+c223=a+b2+a(2)2

f3t=a+bt3+c3213=a+b3+a(3)2

02

Rearrange the terms of the above equations

Consider the simplified equations.

-1=a+b+c.......(1)3=a+2b+4c......(2)13=a+3b+9c......(3)

03

Solve the above equations (1), (2) and (3)

Arrange the equations (1), (2) and (3) into matrix form:

111124139abc=-1313

Upon solving the values of a,b and c are obtained as a=1,b=-5,c=3..

Substitute these values in the standard equation of the 2 degree polynomial. ft=1+(-5)t+(3)t2ft=1-5t+3t2

The graph of the polynomial ft=1-5t+3t2 is,

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