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In Exercises 29 – 32, (a) does the equation \(A{\mathop{\rm x}\nolimits} = {\mathop{\rm b}\nolimits} \) have a nontrivial solution and (b) does the equation \(Ax = b\) have at least one solution for every possible \({\mathop{\rm b}\nolimits} \)?

30. \(A\) is a \(3 \times 3\) matrix with three pivot positions.

Short Answer

Expert verified

a. The equation \(Ax = 0\) contains one free variable. Thus, the equation \(Ax = 0\) has a nontrivial solution.


b. The equation \(Ax = b\) cannot have a solution for every value of \(b\).

Step by step solution

01

Determine the basic variable and free variable of the matrix

The variables corresponding to pivot columns in the matrix are called basic variables.The other variable is called a free variable.

\(3 \times 3\) matrix has two basic variables and one free variable.

02

Determine whether the equation \(Ax = b\) has a nontrivial solution

(a)

The homogeneous equation \(Ax = 0\) will have anontrivial solutionif and only if the equation has at least one free variable.The system will have a nontrivial solution if a column in the coefficient matrix does not construct a pivot column.

\(A\) is a \(3 \times 3\) matrix with two pivot positions since the equation \(Ax = 0\) contains two basic variables and one free variable. Therefore, the equation \(Ax = 0\) has a nontrivial solution.

03

Determine whether the equation \(Ax = b\) has at least one solution for every possible \({\mathop{\rm b}\nolimits} \)

(b)

Theorem 4states that \(A\) is a \({\mathop{\rm m}\nolimits} \times n\) matrix. Hence, the following statement is equivalent. For a particular \(A\), either they are all true statements or false statements.

  1. For each \({\mathop{\rm b}\nolimits} \) in \({\mathbb{R}^m}\), the equation \(Ax = b\) has a solution.
  2. Each \({\mathop{\rm b}\nolimits} \) in \({\mathbb{R}^m}\) is a linear combination of the columns of A.
  3. The columns of \(A\) span .
  4. \(A\)has a pivot position in every row.

Since there are only two pivot positions in the matrix \(A\), so \(A\) cannot have a pivot position in every row. According to theorem 4, the equation \(Ax = b\) cannot have a solution for every value of \({\mathop{\rm b}\nolimits} \).

Thus, the equation \(Ax = b\) cannot have a solution for every value of \(b\).

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