/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q26E Construct three different augmen... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Construct three different augmented matrices for linear systems whose solution set is \({x_1} = - 2,{x_2} = 1,{x_3} = 0\).

Short Answer

Expert verified

The three different augmented matrices are \(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\0&1&1&1\\0&0&1&0\end{array}} \right]\), \(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\0&1&1&1\\1&0&1&{ - 2}\end{array}} \right]\), and \(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\2&1&1&{ - 3}\\1&0&1&{ - 2}\end{array}} \right]\).

Step by step solution

01

Write the given solution set in an augmented matrix

To express a system in theaugmented matrix form, extract the coefficients of the variables and the constants, and place these entries in the column of the matrix.

Now, begin with a simple augmented matrix for which the solution is \({x_1} = - 2\), \({x_2} = 1\), \({x_3} = 0\).

For the solution set \({x_1} = - 2\), \({x_2} = 1\), \({x_3} = 0\), the augmented matrix is as follows:

\(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\0&1&0&1\\0&0&1&0\end{array}} \right]\)

02

Apply the row operation

A basic principle states that row operations do not affect the solution set of a linear system.

Perform an elementary row operation on the matrix \(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\0&1&0&1\\0&0&1&0\end{array}} \right]\) to produce the first augmented matrix.

Replace row two with the sum of the second and the third rows; i.e., \({R_2} \to {R_2} + {R_3}\).

\(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\{0 + 0}&{1 + 0}&{0 + 1}&{1 + 0}\\0&0&1&0\end{array}} \right]\)

\(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\0&1&1&1\\0&0&1&0\end{array}} \right]\)

03

Apply the row operation

Perform an elementary row operation on the matrix \(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\0&1&1&1\\0&0&1&0\end{array}} \right]\) to produce the second augmented matrix.

Replace row three with the sum of rows one and three; i.e., \({R_3} \to {R_3} + {R_1}\).

\(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\0&1&1&1\\{0 + 1}&{0 + 0}&{1 + 0}&{0 - 2}\end{array}} \right]\)

After the row operation, the matrix becomes the following:

\(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\0&1&1&1\\1&0&1&{ - 2}\end{array}} \right]\)

04

Apply the row operation

Perform an elementaryrow operation on the matrix \(\left( {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\0&1&1&1\\1&0&1&{ - 2}\end{array}} \right)\) to produce the third augmented matrix.

Replace row two with the sum of rows one and two; i.e., \({R_2} \to {R_2} + 2{R_1}\).

\(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\{0 + 2\left( 1 \right)}&{1 + 2\left( 0 \right)}&{1 + 2\left( 0 \right)}&{1 + 2\left( { - 2} \right)}\\1&0&1&{ - 2}\end{array}} \right]\)

After the row operation, the matrix becomes the following:

\(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\2&1&1&{ - 3}\\1&0&1&{ - 2}\end{array}} \right]\)

Thus, the three different augmented matrices obtained are \(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\0&1&1&1\\0&0&1&0\end{array}} \right]\), \(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\0&1&1&1\\1&0&1&{ - 2}\end{array}} \right]\), and \(\left[ {\begin{array}{*{20}{c}}1&0&0&{ - 2}\\2&1&1&{ - 3}\\1&0&1&{ - 2}\end{array}} \right]\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the general solutions of the systems whose augmented matrices are given as

14. \(\left[ {\begin{array}{*{20}{c}}1&2&{ - 5}&{ - 6}&0&{ - 5}\\0&1&{ - 6}&{ - 3}&0&2\\0&0&0&0&1&0\\0&0&0&0&0&0\end{array}} \right]\).

Suppose Tand Ssatisfy the invertibility equations (1) and (2), where T is a linear transformation. Show directly that Sis a linear transformation. (Hint: Given u, v in \({\mathbb{R}^n}\), let \({\mathop{\rm x}\nolimits} = S\left( {\mathop{\rm u}\nolimits} \right),{\mathop{\rm y}\nolimits} = S\left( {\mathop{\rm v}\nolimits} \right)\). Then \(T\left( {\mathop{\rm x}\nolimits} \right) = {\mathop{\rm u}\nolimits} \), \(T\left( {\mathop{\rm y}\nolimits} \right) = {\mathop{\rm v}\nolimits} \). Why? Apply Sto both sides of the equation \(T\left( {\mathop{\rm x}\nolimits} \right) + T\left( {\mathop{\rm y}\nolimits} \right) = T\left( {{\mathop{\rm x}\nolimits} + y} \right)\). Also, consider \(T\left( {cx} \right) = cT\left( x \right)\).)

In Exercises 19–22, determine the value(s) of \(h\) such that the matrix is the augmented matrix of a consistent linear system.

19. \(\left[ {\begin{array}{*{20}{c}}1&h&4\\3&6&8\end{array}} \right]\)

In Exercise 2, compute \(u + v\) and \(u - 2v\).

2. \(u = \left[ {\begin{array}{*{20}{c}}3\\2\end{array}} \right]\), \(v = \left[ {\begin{array}{*{20}{c}}2\\{ - 1}\end{array}} \right]\).

Exercises 42–44 show how to use the condition number of a matrix Ato estimate the accuracy of a computed solution of \(Ax = b\). If the entries of Aand b are accurate to about rsignificant digits and if the condition number of Ais approximately \({\bf{1}}{{\bf{0}}^k}\) (with ka positive integer), then the computed solution of \(Ax = b\) should usually be accurate to at least \(r - k\) significant digits.

43. Repeat Exercise 42 for the matrix in Exercise 10.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.