/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q1E Let \(A = \left[ {\begin{array}{... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(A = \left[ {\begin{array}{*{20}{c}}2&0\\0&2\end{array}} \right]\), and define \(T:{\mathbb{R}^2} \to {\mathbb{R}^2}\) by \(T\left( {\bf{x}} \right) = A{\bf{x}}\). Find the images under \(T\) of \({\bf{u}} = \left[ {\begin{array}{*{20}{c}}1\\{ - 3}\end{array}} \right]\), and \({\bf{v}} = \left[ {\begin{array}{*{20}{c}}a\\b\end{array}} \right]\).

Short Answer

Expert verified

The images under T of vectors u and v are \(T\left( {\bf{u}} \right) = \left[ {\begin{array}{*{20}{c}}2\\{ - 6}\end{array}} \right]\) and \(T\left( {\bf{v}} \right) = \left[ {\begin{array}{*{20}{c}}{2a}\\{2b}\end{array}} \right]\).

Step by step solution

01

Write the concept for computing images under the transformation of vectors

The multiplication of matrix\(A\)of the order\(m \times n\)and vector x gives a new vector defined as\(A{\bf{x}}\)or b.

This concept is defined by the transformation rule \(T\left( {\bf{x}} \right)\). The matrix transformation is denoted as \({\bf{x}}| \to A{\bf{x}}\).

02

Obtain the image of vector u under transformation T

Consider the transformation\(T\left( {\bf{x}} \right) = A{\bf{x}}\).

Substitute ufor x in the transformation \(T\left( {\bf{x}} \right) = A{\bf{x}}\)to obtain the image of vector u under transformation T.

\(T\left( {\bf{u}} \right) = A{\bf{u}}\)

Substitute matrix\(A = \left[ {\begin{array}{*{20}{c}}2&0\\0&2\end{array}} \right]\)and\({\bf{u}} = \left[ {\begin{array}{*{20}{c}}1\\{ - 3}\end{array}} \right]\)in\(T\left( {\bf{u}} \right) = A{\bf{u}}\), as shown below:

\(\begin{aligned}{c}T\left( {\bf{u}} \right) &= \left[ {\begin{array}{*{20}{c}}2&0\\0&2\end{array}} \right]\left[ {\begin{array}{*{20}{c}}1\\{ - 3}\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}{2\left( 1 \right) + 0\left( { - 3} \right)}\\{0\left( 1 \right) + 2\left( { - 3} \right)}\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}2\\{ - 6}\end{array}} \right]\end{aligned}\)

Thus, \(T\left( {\bf{u}} \right) = \left[ {\begin{array}{*{20}{c}}2\\{ - 6}\end{array}} \right]\).

03

Obtain the image of vector v under transformation T

Substitute vfor x in the transformation \(T\left( {\bf{x}} \right) = A{\bf{x}}\)to obtain the image of vector v under transformation T.

\(T\left( {\bf{v}} \right) = A{\bf{v}}\)

Substitute matrix\(A = \left[ {\begin{array}{*{20}{c}}2&0\\0&2\end{array}} \right]\)and\({\bf{v}} = \left[ {\begin{array}{*{20}{c}}a\\b\end{array}} \right]\)in\(T\left( {\bf{v}} \right) = A{\bf{v}}\), as shown below:

\(\begin{aligned}{c}T\left( {\bf{v}} \right) &= \left[ {\begin{array}{*{20}{c}}2&0\\0&2\end{array}} \right]\left[ {\begin{array}{*{20}{c}}a\\b\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}{2\left( a \right) + 0\left( b \right)}\\{0\left( a \right) + 2\left( b \right)}\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}{2a}\\{2b}\end{array}} \right]\end{aligned}\)

Thus, \(T\left( {\bf{v}} \right) = \left[ {\begin{array}{*{20}{c}}{2a}\\{2b}\end{array}} \right]\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercise 2, compute \(u + v\) and \(u - 2v\).

2. \(u = \left[ {\begin{array}{*{20}{c}}3\\2\end{array}} \right]\), \(v = \left[ {\begin{array}{*{20}{c}}2\\{ - 1}\end{array}} \right]\).

Consider a dynamical systemwith two components. The accompanying sketch shows the initial state vectorx→0and two eigen vectorsυ1→  and  υ2→of A (with eigen values λ1→andλ2→respectively). For the given values ofλ1→andλ2→, draw a rough trajectory. Consider the future and the past of the system.

λ1→=0.9,λ2→=0.9

Suppose Ais an \(n \times n\) matrix with the property that the equation \(Ax = 0\)has only the trivial solution. Without using the Invertible Matrix Theorem, explain directly why the equation \(Ax = b\) must have a solution for each b in \({\mathbb{R}^n}\).

Suppose the system below is consistent for all possible values of \(f\) and \(g\). What can you say about the coefficients \(c\) and \(d\)? Justify your answer.

27. \(\begin{array}{l}{x_1} + 3{x_2} = f\\c{x_1} + d{x_2} = g\end{array}\)

In (a) and (b), suppose the vectors are linearly independent. What can you say about the numbers \(a,....,f\) ? Justify your answers. (Hint: Use a theorem for (b).)

  1. \(\left( {\begin{aligned}{*{20}{c}}a\\0\\0\end{aligned}} \right),\left( {\begin{aligned}{*{20}{c}}b\\c\\d\end{aligned}} \right),\left( {\begin{aligned}{*{20}{c}}d\\e\\f\end{aligned}} \right)\)
  2. \(\left( {\begin{aligned}{*{20}{c}}a\\1\\0\\0\end{aligned}} \right),\left( {\begin{aligned}{*{20}{c}}b\\c\\1\\0\end{aligned}} \right),\left( {\begin{aligned}{*{20}{c}}d\\e\\f\\1\end{aligned}} \right)\)
See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.