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In Exercises 15 and 16, list five vectors in Span \(\left\{ {{v_1},{v_2}} \right\}\). For each vector, show the weights on \({{\mathop{\rm v}\nolimits} _1}\) and \({{\mathop{\rm v}\nolimits} _2}\) used to generate the vector and list the three entries of the vector. Do not make a sketch.

16. \({{\mathop{\rm v}\nolimits} _1} = \left[ {\begin{array}{*{20}{c}}3\\0\\2\end{array}} \right],{v_2} = \left[ {\begin{array}{*{20}{c}}{ - 2}\\0\\3\end{array}} \right]\)

Short Answer

Expert verified

The five vectors in span \(\left\{ {{v_1},{v_2}} \right\}\) are \(\left\{ {\left[ {\begin{array}{*{20}{c}}0\\0\\0\end{array}} \right],\left[ {\begin{array}{*{20}{c}}3\\0\\2\end{array}} \right],\left[ {\begin{array}{*{20}{c}}{ - 2}\\0\\3\end{array}} \right],\left[ {\begin{array}{*{20}{c}}1\\0\\5\end{array}} \right],\left[ {\begin{array}{*{20}{c}}5\\0\\{ - 1}\end{array}} \right]} \right\}\).

Step by step solution

01

Choose the five sets of weights to generate the vector

The vector\({\mathop{\rm y}\nolimits} \)defined by\(y = {c_1}{v_1} + .... + {c_p}{v_p}\)is called alinear combination of\({{\mathop{\rm v}\nolimits} _1},{v_2},...,{v_p}\)with weights\({c_1},{c_2},...,{c_p}\).

Choose the five sets of weights as:

\({\rm{w}} = \left\{ {0,0} \right\},\left\{ {1,0} \right\},\left\{ {0,1} \right\},\left\{ {1,1} \right\},\left\{ {1, - 1} \right\}\)

02

Generate the weight of the first vector

In\({\mathbb{R}^2}\), the sum of two vectors\({\mathop{\rm u}\nolimits} \)and\({\mathop{\rm v}\nolimits} \)is thevector addition \({\mathop{\rm u}\nolimits} + v\), which is obtained by adding the corresponding entries of\({\mathop{\rm u}\nolimits} \)and\({\mathop{\rm v}\nolimits} \).

Thescalar multipleof a vector \({\mathop{\rm u}\nolimits} \) by real number \(c\) is the vector \(c{\mathop{\rm u}\nolimits} \) obtained by multiplying each entry in \({\mathop{\rm u}\nolimits} \) by \(c\).

Use scalar multiplication and vector addition to generate the weight of the vector

\(\begin{aligned}{c}{V_1} &= 0{v_1} + 0{v_2}\\ &= 0\left[ {\begin{array}{*{20}{c}}3\\0\\2\end{array}} \right] + 0\left[ {\begin{array}{*{20}{c}}{ - 2}\\0\\3\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}0\\0\\0\end{array}} \right]\end{aligned}\)

03

Generate the weight of the second vector

If \({{\mathop{\rm v}\nolimits} _1},{v_2},...,{v_p}\) in \({\mathbb{R}^n}\), then the set of all linear combinations \({{\mathop{\rm v}\nolimits} _1},{v_2},...,{v_p}\) is denoted by span \(\left\{ {{{\mathop{\rm v}\nolimits} _1},{v_2},...,{v_p}} \right\}\) and is called the subset of \({\mathbb{R}^n}\) spanned \({{\mathop{\rm v}\nolimits} _1},{v_2},...,{v_p}\). Span is the collection of all vectors that can be written in the form \({c_1}{v_1} + {c_2}{v_2} + .... + {c_p}{v_p}\) of \({c_1},...,{c_p}\) scalars.

Use scalar multiplication and vector addition to generate the weight of the vector

\(\begin{aligned}{c}{V_2} &= 1{v_1} + 0{v_2}\\ &= 1\left[ {\begin{array}{*{20}{c}}3\\0\\2\end{array}} \right] + 0\left[ {\begin{array}{*{20}{c}}{ - 2}\\0\\3\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}{3 + 0}\\{0 + 0}\\{2 + 0}\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}3\\0\\2\end{array}} \right]\end{aligned}\)

04

Generate the weight of the third vector

Use scalar multiplication and vector addition to generate the weight of the vector

\(\begin{aligned}{c}{V_3} &= 0{v_1} + 1{v_2}\\ &= 0\left[ {\begin{array}{*{20}{c}}3\\0\\2\end{array}} \right] + 1\left[ {\begin{array}{*{20}{c}}{ - 2}\\0\\3\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}{ - 2}\\0\\3\end{array}} \right]\end{aligned}\)

05

Generate the weight of the fourth vector

Use scalar multiplication and vector addition to generate the weight of the vector

\(\begin{aligned}{c}{v_4} &= 1{v_1} + 1{v_2}\\ &= 1\left[ {\begin{array}{*{20}{c}}3\\0\\2\end{array}} \right] + 1\left[ {\begin{array}{*{20}{c}}{ - 2}\\0\\3\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}{3 - 2}\\{0 + 0}\\{2 + 3}\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}1\\0\\5\end{array}} \right]\end{aligned}\)

06

Generate the weight of the fifth vector

Use scalar multiplication and vector addition to generate the weight of the vector

\(\begin{aligned}{c}{V_5} &= 1{v_1} - 1{v_2}\\ &= 1\left[ {\begin{array}{*{20}{c}}3\\0\\2\end{array}} \right] - 1\left[ {\begin{array}{*{20}{c}}{ - 2}\\0\\3\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}{3 + 2}\\{0 + 0}\\{2 - 3}\end{array}} \right]\\ &= \left[ {\begin{array}{*{20}{c}}5\\0\\{ - 1}\end{array}} \right]\end{aligned}\)

07

List the three entries of the vector

The weights on \({v_1}\) and \({v_2}\) to generate the vector are \(\left\{ {0,0} \right\},\left\{ {1,0} \right\},\left\{ {2,3} \right\},\left\{ {1,1} \right\},\left\{ {1, - 1} \right\}\)

The three entries of the vector are \(\left\{ {\left[ {\begin{array}{*{20}{c}}0\\0\\0\end{array}} \right],\left[ {\begin{array}{*{20}{c}}3\\0\\2\end{array}} \right],\left[ {\begin{array}{*{20}{c}}0\\0\\{13}\end{array}} \right]} \right\}\)

Hence, the five vectors in span \(\left\{ {{v_1},{v_2}} \right\}\) are \(\left\{ {\left[ {\begin{array}{*{20}{c}}0\\0\\0\end{array}} \right],\left[ {\begin{array}{*{20}{c}}3\\0\\2\end{array}} \right],\left[ {\begin{array}{*{20}{c}}{ - 2}\\0\\3\end{array}} \right],\left[ {\begin{array}{*{20}{c}}1\\0\\5\end{array}} \right],\left[ {\begin{array}{*{20}{c}}5\\0\\{ - 1}\end{array}} \right]} \right\}\).

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Most popular questions from this chapter

In Exercises 23 and 24, key statements from this section are either quoted directly, restated slightly (but still true), or altered in some way that makes them false in some cases. Mark each statement True or False, and justify your answer. (If true, give the approximate location where a similar statement appears, or refer to a de铿乶ition or theorem. If false, give the location of a statement that has been quoted or used incorrectly, or cite an example that shows the statement is not true in all cases.) Similar true/false questions will appear in many sections of the text.

23.

a. Every elementary row operation is reversible.

b. A \(5 \times 6\)matrix has six rows.

c. The solution set of a linear system involving variables \({x_1},\,{x_2},\,{x_3},........,{x_n}\)is a list of numbers \(\left( {{s_1},\, {s_2},\,{s_3},........,{s_n}} \right)\) that makes each equation in the system a true statement when the values \ ({s_1},\, {s_2},\, {s_3},........,{s_n}\) are substituted for \({x_1},\,{x_2},\,{x_3},........,{x_n}\), respectively.

d. Two fundamental questions about a linear system involve existence and uniqueness.

Consider the problem of determining whether the following system of equations is consistent:

\(\begin{aligned}{c}{\bf{4}}{x_1} - {\bf{2}}{x_2} + {\bf{7}}{x_3} = - {\bf{5}}\\{\bf{8}}{x_1} - {\bf{3}}{x_2} + {\bf{10}}{x_3} = - {\bf{3}}\end{aligned}\)

  1. Define appropriate vectors, and restate the problem in terms of linear combinations. Then solve that problem.
  1. Define an appropriate matrix, and restate the problem using the phrase 鈥渃olumns of A.鈥
  1. Define an appropriate linear transformation T using the matrix in (b), and restate the problem in terms of T.

Give an example of an inconsistent underdetermined system of two equations in three unknowns.

Give a geometric description of Span \(\left\{ {{v_1},{v_2}} \right\}\) for the vectors in Exercise 16.

A system of linear equations with more equations than unknowns is sometimes called an overdetermined system. Can such a system be consistent? Illustrate your answer with a specific system of three equations in two unknowns.

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