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Let \({\mathop{\rm u}\nolimits} = \left( {\begin{array}{*{20}{c}}0\\4\\4\end{array}} \right)\) and \(A = \left( {\begin{array}{*{20}{c}}3&{ - 5}\\{ - 2}&6\\1&1\end{array}} \right)\). Is \({\mathop{\rm u}\nolimits} \) in the plane \({\mathbb{R}^3}\) spanned by the columns of \(A\)?(see the figure.) Why or why not?

Short Answer

Expert verified

\(Ax = u\) has the solution and \(u\) is in the plane \({\mathbb{R}^3}\) spanned by the columns of \(A\).

Step by step solution

01

Writing the matrix in the augmented form

The augmented form \(\left[ {\begin{array}{*{20}{c}}A&u\end{array}} \right]\) of the given matrix is

\(\left[ {\begin{array}{*{20}{c}}3&{ - 5}&0\\{ - 2}&6&4\\1&1&4\end{array}} \right]\).

02

Step 2:Applying the row operation

Perform an elementary row operationto produce the first augmented matrix.

Interchange rows one and three.

\(\left[ {\begin{array}{*{20}{c}}1&1&4\\{ - 2}&6&4\\3&{ - 5}&0\end{array}} \right]\)

03

Step 3:Applying the row operation

Perform an elementary row operationto produce the second augmented matrix.

Write the sum of 2 times row one and row twoin row two.

\(\left[ {\begin{array}{*{20}{c}}1&1&4\\0&8&{12}\\3&{ - 5}&0\end{array}} \right]\)

04

Step 4:Applying the row operation

Perform an elementary row operationto produce the third augmented matrix.

Write the sum of \( - 3\) times row one and row threein row three.

\(\left[ {\begin{array}{*{20}{c}}1&1&4\\0&8&{12}\\0&{ - 8}&{ - 12}\end{array}} \right]\)

05

Step 5:Applying the row operation

Perform an elementary row operationto produce the fourth augmented matrix.

Write the sum of rowstwo and row threein row three.

\(\left[ {\begin{array}{*{20}{c}}1&1&4\\0&8&{12}\\0&0&0\end{array}} \right]\)

06

Converting the matrix in the equation form

To obtain the solution of the vector equation, convert the augmented matrix into vector equations.

Write the obtained matrix \(\left[ {\begin{array}{*{20}{c}}1&1&4\\0&8&{12}\\0&0&0\end{array}} \right]\)into the equation notation.

\(\begin{array}{c}{x_1} + {x_2} = 4\\8{x_2} = 12\end{array}\)

07

Identifying whether \(u\) is in the plane\({\mathbb{R}^3}\) spanned by the columns of \(A\) 

Every \(b\) in \({\mathbb{R}^m}\) is a linear combination of the columns of \(A\). A set of vectors \(\left\{ {{v_1},...,{v_p}} \right\}\)in \({\mathbb{R}^m}\) spans \({\mathbb{R}^m}\) if every vector in \({\mathbb{R}^m}\) is a linear combination of \({v_1},...,{v_p}\). The vector \(u\) lies in the plane spanned by the columns of \(A\) if and only if it is a linear combination of the columns \(A\). This, in turn, occurs if and only if the equation \(Ax = u\) has a solution.

Therefore, \(Ax = u\) has a solution and \(u\) is in the plane \({\mathbb{R}^3}\) spanned by the columns of \(A\).

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Most popular questions from this chapter

In Exercises 13 and 14, determine if \(b\) is a linear combination of the vectors formed from the columns of the matrix \(A\).

13. \(A = \left[ {\begin{array}{*{20}{c}}1&{ - 4}&2\\0&3&5\\{ - 2}&8&{ - 4}\end{array}} \right],{\mathop{\rm b}\nolimits} = \left[ {\begin{array}{*{20}{c}}3\\{ - 7}\\{ - 3}\end{array}} \right]\)

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(b)

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6. \({x_1}\left[ {\begin{array}{*{20}{c}}{ - 2}\\3\end{array}} \right] + {x_2}\left[ {\begin{array}{*{20}{c}}8\\5\end{array}} \right] + {x_3}\left[ {\begin{array}{*{20}{c}}1\\{ - 6}\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}0\\0\end{array}} \right]\)

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