91Ó°ÊÓ

For anyDynamical Systemwith matrix \(A\), the eigenvalues of \(A\) will determine the system of:

\(\begin{aligned}{l}{\rm{Greatest attraction }} \to {\rm{if }}\lambda < 1\\{\rm{Greatest repulsion }} \to {\rm{if }}\lambda > 1\end{aligned}\)

The given matrix for the dynamic system \({{\bf{x}}_{k + 1}} = A{{\bf{x}}_k}\) is:

\(A = \left( {\begin{aligned}{}{1.7}&{}&{.6}\\{ - .4}&{}&{.7}\end{aligned}} \right)\)

For eigenvalues, we have:

\(\begin{aligned}{}\det \left( {A - \lambda I} \right) = 0\\\left| {\begin{aligned}{}{1.7 - \lambda }&{}&{0.6}\\{ - 0.4}&{}&{0.7 - \lambda }\end{aligned}} \right| = 0\\{\lambda ^2} - 2.4\lambda + 1.43 = 0\\\lambda = 1.1,1.3\end{aligned}\)

Here, both the eigenvalues are greater than 1.

Hence, the origin is a repellor.

Now, for eigenvectors, we have:

At \(\lambda = 1.3\).

\(\begin{aligned}{}\left( {A - \left( {1.3} \right)I} \right){v_1} &= 0\\\left( {\begin{aligned}{}{1.7 - 1.3}&{}&{0.6}\\{ - 0.4}&{}&{0.7 - 1.3}\end{aligned}} \right)\left( {\begin{aligned}{}x\\y\end{aligned}} \right) &= 0\\\left( {\begin{aligned}{}{0.4}&{}&{0.6}\\{ - 0.4}&{}&{ - 0.6}\end{aligned}} \right)\left( {\begin{aligned}{}x\\y\end{aligned}} \right) &= 0\end{aligned}\)

Also, the system of equationwill be:

\(\begin{aligned}{}0.4x + 0.6y = 0\\ - 0.4x - 0.6y = 0\end{aligned}\)

For this, the general solution, we have:

\(\begin{aligned}{}{v_1} &= \left( {\begin{aligned}{}x\\y\end{aligned}} \right)\\ &= \left( {\begin{aligned}{}{ - \frac{6}{4}y}\\y\end{aligned}} \right)\\ &= \left( {\begin{aligned}{}{ - 6}\\4\end{aligned}} \right)\\ &= \left( {\begin{aligned}{}{ - 3}\\2\end{aligned}} \right)\end{aligned}\)

Here, the eigenvector is: \({v_1} = \left( {\begin{aligned}{}{ - 3}\\2\end{aligned}} \right)\).

Hence, the direction of greatest repulsion is through the origin and eigenvector: \({v_1} = \left( {\begin{aligned}{}{ - 3}\\2\end{aligned}} \right)\).