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Verify the statements in Exercises 19–24. The matrices are square.

22. If \(A\) is diagonalizable and B is similar to A, then \(B\) is also diagonalizable.

Short Answer

Expert verified

It is proved that \(B\) is diagonalizable

Step by step solution

01

Similar matrices

When \(A\) is diagonalizable, then \(A\) = PD{P^{ - 1))\) for any \(P\). Moreover, when \(B\) is similar to \(A\), then \(B = QA{Q^{ - 1))\) for any \(Q\).

02

Show that when \(A\) is diagonalizable and \(B\) is similar to \(A\), then \(B\) is also diagonalizable

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Let\(D = \left\{ {{{\bf{d}}_1},{{\bf{d}}_2}} \right\}\) and \(B = \left\{ {{{\bf{b}}_1},{{\bf{b}}_2}} \right\}\) be bases for vector space \(V\) and \(W\), respectively. Let \(T:V \to W\) be a linear transformation with the property that

\(T\left( {{{\bf{d}}_1}} \right) = 2{{\bf{b}}_1} - 3{{\bf{b}}_2}\), \(T\left( {{{\bf{d}}_2}} \right) = - 4{{\bf{b}}_1} + 5{{\bf{b}}_2}\)

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